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postnew [5]
3 years ago
5

Which equation represents the data shown in the table below?

Mathematics
1 answer:
Lorico [155]3 years ago
3 0

Answer:

y = -2x + 7

Step-by-step explanation:

The equation of a line could be represented as original form:

y = ax + b

Let's pick the first 2 pairs of numbers in the table: (x, y) = (1, 5) and (x, y) = (2, 3).

=> 5 = a*1 + b

    3 = a*2 + b

Subtract the 1st equation from the 2nd equation, we have:

-2 = (2a - a) + (b - b)

or

-2 = a

Substitute a = -2 into the 1st equation, we have:

5 = (-2)*1 + b

or

5 = -2 + b

or

b = 2 + 5 = 7

=> Substitute a = -2 and b = 7 into original form, the equation that represents the data shown in the table is:

y = -2x + 7

Hope this helps!

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3 years ago
(6+√25)/(4-√3) can be written in the form of (2+s√3)/13 where r and s are both integers what are the values of r and s
cestrela7 [59]

Answer:

r = 33

s = 18

Step-by-step explanation:

Given expression is \frac{6+\sqrt{27}}{4-\sqrt{3}}.

Multiply numerator and denominator with the conjugate of (4 - √3).  

\frac{(6+\sqrt{27})(4+\sqrt{3})}{(4-\sqrt{3})(4+\sqrt{3})}

= \frac{4(6+\sqrt{27})+\sqrt{3}(6+\sqrt{27})}{4^{2}-(\sqrt{3})^2}

= \frac{24+4\sqrt{27}+6\sqrt{3}+\sqrt{81})}{16-3}

= \frac{24+12\sqrt{3}+6\sqrt{3}+\sqrt{81})}{16-3}

= \frac{24+18\sqrt{3}+9}{13}

= \frac{33+18\sqrt{3}}{13}

Now compare this expression with \frac{r+s\sqrt{3} }{13}

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