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postnew [5]
3 years ago
5

Which equation represents the data shown in the table below?

Mathematics
1 answer:
Lorico [155]3 years ago
3 0

Answer:

y = -2x + 7

Step-by-step explanation:

The equation of a line could be represented as original form:

y = ax + b

Let's pick the first 2 pairs of numbers in the table: (x, y) = (1, 5) and (x, y) = (2, 3).

=> 5 = a*1 + b

    3 = a*2 + b

Subtract the 1st equation from the 2nd equation, we have:

-2 = (2a - a) + (b - b)

or

-2 = a

Substitute a = -2 into the 1st equation, we have:

5 = (-2)*1 + b

or

5 = -2 + b

or

b = 2 + 5 = 7

=> Substitute a = -2 and b = 7 into original form, the equation that represents the data shown in the table is:

y = -2x + 7

Hope this helps!

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Help please <br> Look at picture above
Tatiana [17]

Answer:

18.8 miles.

Step-by-step explanation:

(b)(h)/2 = A.

In this circumstance, you are solving for h.

Isolate h.

h = 2 x A/b

Now, substitute 102.46 for A and 10.9 for b.

h = 2 x 102.46/10.9 = 2 x 9.4 = 18.8.

h = 18.8mi.

6 0
3 years ago
The following sum is a partial sum of an arithmetic sequence; use either formula for finding partial sums of arithmetic sequence
ASHA 777 [7]

Answer:

16008

Step-by-step explanation:

Sum of an arithmetic sequence is:

S = (n/2) (2a₁ + (n−1) d)

or

S = (n/2) (a₁ + a)

To use either equation, we need to find the number of terms n.  We know the common difference d is 1 − (-9) = 10.  Using the definition of the nth term of an arithmetic sequence:

a = a₁ + (n−1) d

561 = -9 + (n−1) (10)

570 = 10n − 10

580 = 10n

n = 58

Using the first equation to find the sum:

S = (n/2) (2a₁ + (n−1) d)

S = (58/2) (2(-9) + (58−1) 10)

S = 29 (-18 + 570)

S = 16008

Using the second equation to find the sum:

S = (n/2) (a₁ + a)

S = (58/2) (-9 + 561)

S = 16008

4 0
3 years ago
Read 2 more answers
Help with this math equation ?
Pavel [41]
I think the answer is 1x+3=7
8 0
3 years ago
5x + 2y=7<br> - 2x + 6y=9
ollegr [7]

Answer:

x = \frac{12}{17} or 0.706

y = \frac{59}{34} or 1.735

Step-by-step explanation:

5x + 2y=7    ----->(eq 1)

- 2x + 6y=9 ----->(eq 2)

Multiply (eq 1) with 3

3×(5x + 2y) = 3×7  

15x + 6y = 21  ----->(eq 3)

substract (eq 3) from (eq 2)

- 2x + 6y - (15x + 6y) = 9-21

- 2x + 6y - 15x - 6y = 9-21

- 2x - 15x + 6y - 6y = 9-21

-17x = -12

x = -12 ÷ -17

x = \frac{12}{17}

put x = \frac{12}{17} in (eq 1)

5*\frac{12}{17} + 2y = 7

2y = 7- 5*\frac{12}{17}

2y = \frac{7*17 - 60}{17}

2y = \frac{119- 60}{17}

2y = \frac{59}{17}

y = \frac{59}{17*2}

y = \frac{59}{34}

6 0
4 years ago
HELP ME A INNOCENT CHILD PLEASSSSSSSSSSSE
agasfer [191]
1 YEAR = 12 months

divide: 5,031 ÷ 12 =  419.25

419 dollars and 25 cents each month

hope it helps!
4 0
4 years ago
Read 2 more answers
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