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postnew [5]
3 years ago
5

Which equation represents the data shown in the table below?

Mathematics
1 answer:
Lorico [155]3 years ago
3 0

Answer:

y = -2x + 7

Step-by-step explanation:

The equation of a line could be represented as original form:

y = ax + b

Let's pick the first 2 pairs of numbers in the table: (x, y) = (1, 5) and (x, y) = (2, 3).

=> 5 = a*1 + b

    3 = a*2 + b

Subtract the 1st equation from the 2nd equation, we have:

-2 = (2a - a) + (b - b)

or

-2 = a

Substitute a = -2 into the 1st equation, we have:

5 = (-2)*1 + b

or

5 = -2 + b

or

b = 2 + 5 = 7

=> Substitute a = -2 and b = 7 into original form, the equation that represents the data shown in the table is:

y = -2x + 7

Hope this helps!

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Answer:

Event A = white marble is selected

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p(B) = 5/10 = 1/2

Probability that A and B are independent events is:

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3 years ago
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How many solutions are there in the given equation?<br> y = 2x² + 6x + 4
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Step-by-step explanation:

Use the quadratic formula

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brainliest and follow and thanks

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3 years ago
An angle measures 70° more than the measure of its supplementary angle. What is the measure of each angle
jekas [21]

Answer:

55° and 125°

Step-by-step explanation:

Formulate an equation x + (x+70) = 180

Combine like terms to get 2x + 70 = 180

Subtract 70 on both sides to get 2x = 110.

Divide both sides by 2 to get x = 55.

Add 70 to 55 to get 125.

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3 years ago
Find the value of x in each case: Given: Iso. ΔABC, HM ∥DG Find: x, m∠CAB, m∠CBA
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1. Start with ΔCIJ.

  • ∠HIC and ∠CIJ are supplementary, then m∠CIJ=180°-7x;
  • the sum of the measures of all interior angles in ΔCIJ is 180°, then m∠CJI=180°-m∠JCI-m∠CIJ=180°-25°-(180°-7x)=7x-25°;
  • ∠CJI and ∠KJA are congruent as vertical angles, then m∠KJA =m∠CJI=7x-25°.

2. Lines HM and DG are parallel, then ∠KJA and ∠JAB are consecutive interior angles, then m∠KJA+m∠JAB=180°. So

m∠JAB=180°-m∠KJA=180°-(7x-25°)=205°-7x.

3. Consider ΔCKL.

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  • ∠CLM and ∠CLK are supplementary, then m∠CLM+m∠CLK=180°, m∠CLK=180°-8x;
  • the sum of the measures of all interior angles in ΔCLK is 180°, then m∠CKL=180°-m∠CLK-m∠LCK=180°-(180°-8x)-42°=8x-42°;
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4. Lines HM and DG are parallel, then ∠JKB and ∠KBA are consecutive interior angles, then m∠JKB+m∠KBA=180°. So

m∠KBA=180°-m∠JKB=180°-(8x-42°)=222°-8x.

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m∠KBA=m∠JAB → 222°-8x=205°-7x,

7x-8x=205°-222°,

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Then m∠CAB=m∠CBA=205°-7x=86°.

Answer: 86°.

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2 years ago
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