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Anna35 [415]
2 years ago
13

Which of the following relations is a function? A. (0, 4), (-2, 6), (0, 3), (-7, 2) B. (8, 1), (-2, 4), (0, 1), (8, 2) C. (0, 4)

, (-2, 2), (8, 1), (-7, 2) D. (0, 0), (-2, 3), (8, 1), (-2, 5)
Mathematics
1 answer:
fomenos2 years ago
8 0

Answer: C

Step-by-step explanation:

C is a function because each of the inputs are distinct, meaning they only have one output each.

The other choices are not functions because at least one of the inputs corresponds to 2 or more outputs.

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3.3 greater than or less than 0.33​
nika2105 [10]

Answer:

Greater Than

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Suppose a random variable x is best described by a uniform probability distribution with range 22 to 55. Find the value of a tha
const2013 [10]

Answer:

(a) The value of <em>a</em> is 53.35.

(b) The value of <em>a</em> is 38.17.

(c) The value of <em>a</em> is 26.95.

(d) The value of <em>a</em> is 25.63.

(e) The value of <em>a</em> is 12.06.

Step-by-step explanation:

The probability density function of <em>X</em> is:

f_{X}(x)=\frac{1}{55-22}=\frac{1}{33}

Here, 22 < X < 55.

(a)

Compute the value of <em>a</em> as follows:

P(X\leq a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.95\times 33=[x]^{a}_{22}\\\\31.35=a-22\\\\a=31.35+22\\\\a=53.35

Thus, the value of <em>a</em> is 53.35.

(b)

Compute the value of <em>a</em> as follows:

P(X< a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.49\times 33=[x]^{a}_{22}\\\\16.17=a-22\\\\a=16.17+22\\\\a=38.17

Thus, the value of <em>a</em> is 38.17.

(c)

Compute the value of <em>a</em> as follows:

P(X\geq  a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.85=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.85\times 33=[x]^{55}_{a}\\\\28.05=55-a\\\\a=55-28.05\\\\a=26.95

Thus, the value of <em>a</em> is 26.95.

(d)

Compute the value of <em>a</em> as follows:

P(X\geq  a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.89=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.89\times 33=[x]^{55}_{a}\\\\29.37=55-a\\\\a=55-29.37\\\\a=25.63

Thus, the value of <em>a</em> is 25.63.

(e)

Compute the value of <em>a</em> as follows:

P(1.83\leq X\leq  a)=\int\limits^{a}_{1.83} {\frac{1}{33}} \, dx \\\\0.31=\frac{1}{33}\cdot \int\limits^{a}_{1.83} {1} \, dx \\\\0.31\times 33=[x]^{a}_{1.83}\\\\10.23=a-1.83\\\\a=10.23+1.83\\\\a=12.06

Thus, the value of <em>a</em> is 12.06.

7 0
3 years ago
2-31. Write an equation and solve it to find the answer to the question below.  Use the 5-D Process to help you write the equati
raketka [301]

r = 25+b

n = 3b

n+r+b=435

3b+25+b+b=435

5b+25=435

5b=210

b=42

r = 25+42 = 67

n = 3(42) = 126

6 0
3 years ago
What value of t makes (-2) +(-11) = t a true sentence?
Bas_tet [7]

Answer:

t = -13

Step-by-step explanation:

Given expression:

  • (-2) +(-11) = t

Solving for t:

  • -13 = t
  • t = -13
8 0
3 years ago
Which equation represents the graph?
frosja888 [35]

Answer:

The answer is A) y+4 =3(x+3)

Step-by-step explanation:

The slope is the rate of change, which you can see from the graph is m = 3/1 = 3.

Your options are given in point-slope form:

y-y1=m(x-x1)

Pick a point from the graph. I used;

(-3, -4). Now plug this into your point slope form equation.

y-(-4) = 3(x-(-3))

y+4=3(x+3)

8 0
3 years ago
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