Height=4.5+√(7.3*age)

Consider a Poisson distribution with μ = 6.

bearhunter [10]

Answer:

a) $P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

b) f(2) = 0.04462

c) f(1) = 0.01487

d) $P(X \geq 2) = 0.93803$

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of successes

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

In this question:

$\mu = 6$

a. Write the appropriate Poisson probability function.

Considering $\mu = 6$

$P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

b. Compute f (2).

This is P(X = 2). So

$P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

$P(X = 2) = \frac{e^{-6}*6^{2}}{(2)!} = 0.04462$

So f(2) = 0.04462

c. Compute f (1).

This is P(X = 1). So

$P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

$P(X = 1) = \frac{e^{-6}*6^{1}}{(1)!} = 0.01487$

So f(1) = 0.01487.

d. Compute P(x≥2)

This is:

$P(X \geq 2) = 1 - P(X < 2)$

In which:

$P(X < 2) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-6}*6^{0}}{(0)!} = 0.00248$

$P(X = 1) = \frac{e^{-6}*6^{1}}{(1)!} = 0.01487$

$P(X = 2) = \frac{e^{-6}*6^{2}}{(2)!} = 0.04462$

Then

$P(X < 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.00248 + 0.01487 + 0.04462 = 0.06197$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.06197 = 0.93803$

So

$P(X \geq 2) = 0.93803$

5 0

2 years ago

Whats the equation of finding for parallel or perpendicular lines?

Anvisha [2.4K]

Answer:

y=mx+b

Step-by-step explanation:

Y is just y

m is the slope

x is the x point

b is the y intercept

4 0

2 years ago

Five over one fifty twoths equals what in fraction

tatiyna

So five over one fifty twoth's means 5/(1/52) to simplify, mutiply the whole fraction by 52/52 so
260/(52/52)=260/1=260
answer is 260

4 0

2 years ago

A large bakery buys flour in 20-pound bags. The bakery uses an average of 1050 bags a year. Preparing an order and receiving a s

emmasim [6.3K]

Given the following:

Demand = 1050
Ordering cost = 15
Holding cost = 55

The economic order quantity is 24.

<h3>What is the economic order Quantity?</h3>

Eoq = √2 * demand * ordering cost / holding cost)

= √(2 * 1050 * 15 / 55)

EOQ = 24

<h3>What is the average number of bags on-hand?</h3>

The Average inventory = EOQ / 2

= 24 / 2

= 12

<h3>How many orders per year will there be?</h3>

Expected number of orders = demand / EOQ

= 1050 / 24

= 44

<h3>What is the total cost of ordering and carrying flour?</h3>

Annual holding cost (AHC) = (EOQ / 2) * Holding cost

= (24 / 2) * 55

= 660

Annual ordering cost (AOC) = (demand / EOQ) * ordering cost

= (1050 / 24) * 15

= 656

Thus,

Total cost of managing = AHC + AOC

= 660 + 656

TCM = 1,316

<h3>If holding costs were to increase by $5 per year, how much would the minimum total annual cost?</h3>

5. For holding cost of 60

EOQ= √(2 * demand * ordering cost / holding cost)

= √(2 * 1050 * 15 / 60)

= 23

Annual holding cost = (EOQ / 2) * holding cost

this gives us

= (23 / 2) * 60

= 690

Annual ordering cost = (demand / EOQ) * ordering cost

= (1050 / 23) * 15

= 685

Total cost of managing = AHC+ AOC

= 690 + 685

= 1375

Change in total annual cost = new - old

= 1375 - 1316

= 59

Learn more about Economic order quantity:
brainly.com/question/26814787
#SPJ1

8 0

1 year ago

Energy Drinks: Popular energy drinks contain green tea extract and caffeine. Do these energy drinks help you lose weight by incr

notka56 [123]

The confounding variable which is controlled by randomly assigning individuals to treatments is: C. the time of day participants drank the beverages.

<h3>What is a confounding variable?</h3>

A confounding variable is also referred to as a confounder and it can be defined as a type of variable that has the ability to influence both the independent and dependent variables.

Also, a confounding variable is usually not accounted for by the researcher and as such it can cause a spurious association between the independent and dependent variables.

In this context, we can infer and logically deduce that the time of day at which participants drank the beverages is a confounding variable which is controlled by randomly assigning individuals to treatments.

Read more on confounding variable here: brainly.com/question/10863424

#SPJ1

3 0

2 years ago

Height=4.5+√(7.3*age)​

Height=4.5+√(7.3*age)