160+100+180+60=500
180/500=0.36=36%
50x36%=18
That's your answer lovely~
Answer:
there is no greatest load
Step-by-step explanation:
Let x and y represent the load capacities of my truck and my neighbor's truck, respectively. We are given two relations:
x ≥ y +600 . . . . . my truck can carry at least 600 pounds more
x ≤ (1/3)(4y) . . . . . my truck carries no more than all 4 of hers
Combining these two inequalities, we have ...
4/3y ≥ x ≥ y +600
1/3y ≥ 600 . . . . . . . subtract y
y ≥ 1800 . . . . . . . . multiply by 3
My truck's capacity is greater than 1800 +600 = 2400 pounds. This is a lower limit. The question asks for an <em>upper limit</em>. The given conditions do not place any upper limit on truck capacity.
Answer:
f=(d-c)/g
Step-by-step explanation:
fg+c=d
fg=d-c
f=(d-c)/g
The degree is 3.
This video explains it pretty well: https://virtualnerd.com/pre-algebra/polynomials-nonlinear-functions/polynomials/monomial-polynomial-degrees/polynomial-degree-definition
4x - 26 = 2x - 4....subtract 2x from both sides
4x - 2x - 26 = -4...add 26 to both sides
4x - 2x = -4 + 26...combine terms
2x = 22...divide both sides by 2
x = 22/2 = 11
OR
4x - 26 = 2x - 4.....subtract 4x from both sides
-26 = 2x - 4x - 4....add 4 to both sides
-26 + 4 = 2x - 4x...combine terms
-22 = -2x....divide both sides by -2
-22/-2 = x
11 = x
