Question

What is the sum of the first 34 numbers in the series below? 147 + 130 + 113 + 96 + . . .

Answer 1

Answer:

-4,539

Step-by-step explanation:

Given series is: 147 + 130 + 113 + 96 + . . .

Where first term a = 147

Common Difference d = 130 - 147 = - 17

No. of terms n = 34

To find: $S_{34}$

By sum of n terms of an Arithmetic Progression, we have:

$S_{n}=\frac{n}{2}[2a + (n-1)d]$

Plugging the values of a, d and n in the above equation, we find:

$S_{34}=\frac{34}{2}[2(147) + (34-1)(-17)]$

$\therefore S_{34}=17[294 + (33)(-17)]$

$\therefore S_{34}=17[294 - 561]$

$\therefore S_{34}=17[-267]$

$\therefore S_{34}=-4,539$

Answer 2

Answer:

79, 62, 45, 28, 11, -6...

Step-by-step explanation:

Just keep subtracting 17