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andre [41]
3 years ago
12

The length of the sides of a square is 10 meters. Find the length of the diagonals of the square

Mathematics
2 answers:
BaLLatris [955]3 years ago
7 0

。☆✼★ ━━━━━━━━━━━━━━  ☾  

Use Pythagoras' theorem:

a^2 + b^2 = c^2

Sub the values in:

10^2 + 10^2 = c^2

200 = c^2

Square root to find the answer:

c = 14.14

Have A Nice Day ❤    

Stay Brainly! ヅ    

- Ally ✧    

。☆✼★ ━━━━━━━━━━━━━━  ☾

Arada [10]3 years ago
6 0

Answer:

d≈14.14m

d=\sqrt{2\\}a=\sqrt{2}·10≈14.14214m

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Farmer Ed has 9,500 meters of fencing,
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<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get:</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: </em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for x</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equation</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equationA = (7500 - 2y)y distribute</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equationA = (7500 - 2y)y distributeA = -2y2 +7500y</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equationA = (7500 - 2y)y distributeA = -2y2 +7500y </em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equationA = (7500 - 2y)y distributeA = -2y2 +7500y You can see that this is a parabola which opens down, meaning that the point of maximum area will be at the vertex, y = </em><em>- </em><em>b</em><em>/2a = -7500/[2(-2)] = 1875</em>

<em>/2a = -7500/[2(-2)] = 1875 </em>

<em>/2a = -7500/[2(-2)] = 1875 x = 7500 - 2(1875) = 3750</em>

<em>/2a = -7500/[2(-2)] = 1875 x = 7500 - 2(1875) = 3750 </em>

<em>/2a = -7500/[2(-2)] = 1875 x = 7500 - 2(1875) = 3750 A = 3750(1875) = 7,031,250 m2</em>

<em>/2a = -7500/[2(-2)] = 1875 x = 7500 - 2(1875) = 3750 A = 3750(1875) = 7,031,250 m2 </em>

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