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3 years ago

The length of the sides of a square is 10 meters. Find the length of the diagonals of the square

Mathematics

2 answers:

BaLLatris [955]3 years ago

7 0

｡☆✼★ ━━━━━━━━━━━━━━ ☾

Use Pythagoras' theorem:

a^2 + b^2 = c^2

Sub the values in:

10^2 + 10^2 = c^2

200 = c^2

Square root to find the answer:

c = 14.14

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Arada [10]3 years ago

6 0

Answer:

d≈14.14m

d= $\sqrt{2\\}$ a= $\sqrt{2}$ ·10≈14.14214m

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Determine all the factors for the following expression(Note: you will need to use the Rational Root Theorem more than one time)

Aleks [24]

ANSWER

Possible rational roots: <span><span>±1,±2,±3,±4,±6,±12</span><span>±1,±2,±3,±4,±6,±12</span></span>

Actual rational roots: <span><span>1,−1,2,−2,−3</span></span>

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3 years ago

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Which is the reciprocal of the mixed number, 5 5/6 ?

kirill [66]

Answer:

6/35

Step-by-step explanation:

5 5/6 = 35/6, the inverse would be 6/35

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3 years ago

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Directions: Calculate the area of a circle using 3.14x the radius

Leokris [45]

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

As we know ~

Area of the circle is :

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

And radius (r) = diameter (d) ÷ 2

[ radius of the circle = half the measure of diameter ]

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<h3>Problem 1</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 4.4\div 2$

$\qquad \sf \dashrightarrow \:r = 2.2 \: mm$

Now find the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {(2.2)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {4.84}^{}$

$\qquad \sf \dashrightarrow \:area \approx 15.2 \: \: mm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 2</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 3.7 \div 2$

$\qquad \sf \dashrightarrow \:r = 1.85 \: \: cm$

Bow, calculate the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (1.85) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 3.4225 {}^{}$

$\qquad \sf \dashrightarrow \:area \approx 10.75 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 3 </h3>

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (8.3) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 68.89$

$\qquad \sf \dashrightarrow \:area \approx216.31 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 4</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 5.8 \div 2$

$\qquad \sf \dashrightarrow \:r = 2.9 \: \: yd$

now, let's calculate area ~

$\qquad \sf \dashrightarrow \:3.14 \times {(2.9)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 8.41$

$\qquad \sf \dashrightarrow \:area \approx26.41 \: \: yd {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 5</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 1 \div 2$

$\qquad \sf \dashrightarrow \:r = 0.5 \: \: yd$

Now, let's calculate area ~

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (0.5) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 0.25$

$\qquad \sf \dashrightarrow \:area \approx0.785 \: \: yd {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 6</h3>

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {(8)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 64$

$\qquad \sf \dashrightarrow \:area = 200.96 \: \: yd {}^{2}$

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8 0

2 years ago

HELP ASAP PLSPLSPLSPLSPLSPLSPLSPLSPLSPLSPLSPLS

notka56 [123]

Answer:

15/6

Step-by-step explanation:

5 0

2 years ago

The volumes of two cubes are 32ft^3 and 1372ft^3

ser-zykov [4K]

Answer:

1) 8 : 343

2) 42.875 or 42 ⅞

3) 4 : 49

4) 16ft²

Step-by-step explanation:

Volume of cube: s³

Surface area of cube: 6s²

_____________________

32ft^3 and 1372ft^3 →

32 : 1372 = 8 : 343

343 / 8 = 42 ⅞ = 42.875

s³ → 6s²

s³ = 8, s = 2, s² = 4.

s³ = 343, s = 7, s² = 49.

These are proportional so it is already in the simplest ratio so it is not necessary to multiply by 6.

s³ → 8 : 343

6s² → 4 : 49

(4 / 49) × 196ft² = 16ft²

4 0

3 years ago