Can someone please give me the answer.
2 answers:
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Answer:
Required Probability = 0.97062
Step-by-step explanation:
We are given that the weights of newborn baby boys born at a local hospital are believed to have a normal distribution with a mean weight of 4016 grams and a standard deviation of 532 grams.
Let X = weight of the newborn baby, so X ~ N()
The standard normal z distribution is given by;
Z = ~ N(0,1)
Now, probability that the weight will be less than 5026 grams = P(X < 5026)
P(X < 5026) = P( <
) = P(Z < 1.89) = 0.97062
Therefore, the probability that the weight will be less than 5026 grams is 0.97062 .
The picture in the attached figure
let
x--------> men voters
y-------> women voters
we know that
y=x+2800------> y-x=2800------> equation 1
step 1
find the percentage of women and men voters
in the graph
central angle by men voters=130°
central angle by women voters=(360°-130°)-------> 230°
by using proportion
men voters
%
women voters
%
remember equation 1
y-x=2800
so
F-M=63.89%-36.11%----> 27.78%
if 27.78% correspond to 2800 voters
100%---------------------->T
T=100*2800/27.78-------> T=10,079.19 voters
the answer is
about 10,079 voters
let
x--------> men voters
y-------> women voters
we know that
y=x+2800------> y-x=2800------> equation 1
step 1
find the percentage of women and men voters
in the graph
central angle by men voters=130°
central angle by women voters=(360°-130°)-------> 230°
by using proportion
men voters
women voters
remember equation 1
y-x=2800
so
F-M=63.89%-36.11%----> 27.78%
if 27.78% correspond to 2800 voters
100%---------------------->T
T=100*2800/27.78-------> T=10,079.19 voters
the answer is
about 10,079 voters