As for this problem, the most probable and the most likely answer to this would be it depends on the person or the user of it since there aren't any options presented with the problem.
WordArt is there to be of use during presentations, during discussions, and other things. On the other hand, as the technological advancement takes leaps and bounds going forward, this utility seems to be underused and isn't expected to give a more impact to the reader or to the recipient of such document that contains it. This is typically used for people that aren't too familiar yet, as to how to utilize other programs to enhance their documents and files.
Alternative 1:A small D-cache with a hit rate of 94% and a hit access time of 1 cycle (assume that no additional cycles on top of the baseline CPI are added to the execution on a cache hit in this case).Alternative 2: A larger D-cache with a hit rate of 98% and the hit access time of 2 cycles (assume that every memory instruction that hits into the cache adds one additional cycle on top of the baseline CPI). a)[10%] Estimate the CPI metric for both of these designs and determine which of these two designsprovides better performance. Explain your answers!CPI = # Cycles / # InsnLet X = # InsnCPI = # Cycles / XAlternative 1:# Cycles = 0.50*X*2 + 0.50*X(0.94*2 + 0.06*150)CPI= 0.50*X*2 + 0.50*X(0.94*2 + 0.06*150) / X1= X(0.50*2 + 0.50(0.94*2 + 0.06*150) ) / X= 0.50*2 + 0.50(0.94*2 + 0.06*150)= 6.44Alternative 2:# Cycles = 0.50*X*2 + 0.50*X(0.98*(2+1) + 0.02*150)CPI= 0.50*X*2 + 0.50*X(0.98*(2+1) + 0.02*150) / X2= X(0.50*2 + 0.50(0.98*(2+1) + 0.02*150)) / X= 0.50*2 + 0.50(0.98*(2+1) + 0.02*150)= 3.97Alternative 2 has a lower CPI, therefore Alternative 2 provides better performance.
A. should be the answer hope this helps :)
Answer:
public static void print_popcorn_time(int bag_ounces){
if(bag_ounces<3){
System.out.println("Too Small");
}
else if(bag_ounces>10){
System.out.println("Too Large");
}
else{
bag_ounces*=6;
System.out.println(bag_ounces+" seconds");
}
}
Explanation:
Using Java prograamming Language.
The Method (function) print_popcorn_time is defined to accept a single parameter of type int
Using if...else if ....else statements it prints the expected output given in the question
A complete java program calling the method is given below
public class num6 {
public static void main(String[] args) {
int bagOunces = 7;
print_popcorn_time(bagOunces);
}
public static void print_popcorn_time(int bag_ounces){
if(bag_ounces<3){
System.out.println("Too Small");
}
else if(bag_ounces>10){
System.out.println("Too Large");
}
else{
bag_ounces*=6;
System.out.println(bag_ounces+" seconds");
}
}
}
Answer: float
Explanation:
This is asking what would the remainder be of 5/2. I am not totally sure what you are asking but float is used with remainders because it could have a decimal like 3.33 that would throw an error for anything other than float.
