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3 years ago

11

Given: F(x) = 2x 2 + 1, G(x) = 2x - 1, H(x) = x G -1 (x) =

1 answer:

Crazy boy [7]3 years ago

4 0

Answer:

2x-2

Step-by-step explanation:

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Marie joined a book club. She had to pay a one time registration fee of 80.00 and then 3.00 per book.How much did it cost her to

Rasek [7]

Answer:

It cost her this much = 3×15 = 45

5 0

2 years ago

Read 2 more answers

Find the value of x in the triangle shown below.<br> 79°<br> 73<br> PLEASE I NEED THE ANSWER RN

WARRIOR [948]

Answer:

The sum of the three inside angles of a triangle need to equal 180 degrees.

X = 180 - 79 - 73

x = 28 degrees

3 0

2 years ago

A particular brand of gasoline has a density of 0.737 g/ml at 25 ∘c. how many grams of this gasoline would fill a 13.4 gal tank

ruslelena [56]

Given, the density of a particular brand of gasoline = 0.737 g/ml.

13.4 gallon of tank given. We have to find the mass of gasoline to fill the tank.

First we will convert 13.4 gallon to ml.

We know that 1 gallon = 3.78541 litre

And 1 litre = 1000 ml

So we can write 1 gallon = $(3.78541)(1000) ml$ = 3785.41 ml.

13.4 gallon = $(3785.41)(13.4)$ ml = 50724.494 ml.

Let's take there is x grams of gasoline

We know that density = (mass/ volume) = $\frac{x}{50724.494}$

So we can write,

$0.737 =\frac{x}{50724.494}$

To find x we will multiply both sides by 50724.494. we will get,

$(0.737)(50724.494) =(\frac{x}{50724.494}) (50724.494)$

$(0.737)(50724.494) = x$

$37383.95 = x$

So we have got the required answer.

Mass of gasoline = 37383.95 grams.

5 0

3 years ago

Estimate -9 1/6 + 2 1/3 +(-1 7/8

Kobotan [32]

I think it would be around -8.
Hope it helps!

7 0

2 years ago

Ancient paintings were found on cave walls in South America. The Carbon-14 in the paintings was measured and was found to be 19%

balu736 [363]

Answer: C. 13,839 (the answer is not among the given options, however the result is near this value)

Step-by-step explanation:

The exponential decay model for Carbon- 14 is given by the followig formula:

$A=A_{o}e^{-0.0001211.t}$ (1)

Where:

$A$ is the final amount of Carbon- 14

$A_{o}=$ is the initial amount of Carbon- 14

$t$ is the time elapsed (the value we want to find)

On the other hand, we are told the current amount of Carbon-14 $A$ is $19\%=0.19$ , assuming the initial amount of Carbon-14 $A_{o}=$ is $100\%$ :

$A=0.19A_{o}$ (2)

This means: $\frac{A}{A_{o}}=0.19$ (2)

Now,finding $t$ from (1):

$\frac{A}{A_{o}}=e^{-0.0001211.t}$ (3)

Applying natural logarithm on both sides:

$ln(\frac{A}{A_{o}})=ln(e^{-0.0001211.t})$ (4)

$ln(0.19)=-0.0001211.t$ (5)

$t=\frac{ln(0.19)}{-0.0001211}$ (6)

Finally:

$t=13713.717years$ This is the age of the paintings and the option that is nearest to this value is C. 13839 years

6 0

2 years ago