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Alex
3 years ago
8

Prove (sinxsiny-cosxcosy)(sinxsiny+cosxcosy) =sin^2x-cos^2y

Mathematics
1 answer:
3241004551 [841]3 years ago
7 0

Step-by-step explanation:

Recall that \sin^2x + \cos^2x = 1

(\sin x \sin y - \cos x \cos y)(\sin x \sin y + \cos x \cos y)

= \sin^2 x \sin^2 y - \cos^2 x \cos^2 y

= \sin^2 x (1 - \cos^2 y) - \cos^2 x \cos^2 y

= \sin^2 x - \sin^2 x \cos^2y - \cos^2x \cos^2y

= \sin^2x - (\sin^2x + \cos^2x)\cos^2y

= \sin^2x - \cos^2y

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If D is the midpoint of CE, CD= 9x-7, and DE= 3x+17, find CE
tatuchka [14]
Hello!

Since D is the midpoint and the two equations are and both sides of point D the equations equal each other

9x - 7 = 3x + 17

Now you solve it algebraically

Add 7 to both sides

9x = 3x + 24

Subtract 3x from both sides

6x = 24

Divide both sides by 6

x = 4

Now we put this into both equations and add them

9(4) - 7 = 29
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29 + 29 = 58

The answer is 58 units

Hope this helps!
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3 years ago
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irina [24]

Answer:

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8 0
3 years ago
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Lena [83]

It should be noted that angle 2 and angle 1 are vertical angles and angle 2 and angle 5 are linear pair.

<h3>How to illustrate the information?</h3>

When two lines cross at a point, vertical angles are created. They are always on an equal footing. In other words, four angles are created anytime two lines cross or intersect. It is evident that two opposed angles are equal and are referred to as vertical angles.

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Therefore, it should be noted that angle 2 and angle 1 are vertical angles and angle 2 and angle 5 are linear pair.

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brainly.com/question/14362353

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7 0
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Answer:

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Step-by-step explanation:

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