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mojhsa [17]
2 years ago
13

Helppppppppppppppppp

Mathematics
1 answer:
Gwar [14]2 years ago
5 0

Answer:

30

Step-by-step explanation:

40-10=30 so N has to be 30

Your answers are N=30 and N-25=5

Hope this helps :)

1 thanks for me=1 thanks for you

5 stars=3 thanks for you

Brainliest for me=5 thanks for you

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A drop of oil makes a circular ring in a water puddle. The radius of the oil ring expands at 1.5 cm per second. If r(t)=1.5t and
Readme [11.4K]

Answer:

a(t) =n(0.25t^2)

Step-by-step explanation:

Given

r(t) = 0.5t

a(r) = nr^2

Required

Determine the area in terms of time

From the question, we have:

r(t) = 0.5t -> radius per time

and

a(r) = nr^2 --> area from radius

The interpretation of the question is to find the composite function: a(t)

If a(r) = nr^2, and r(t) = 0.5t, the

Substitute 0.5t for r

a(t) =n(0.5t)^2

a(t) =n*0.25t^2

a(t) =n(0.25t^2)

5 0
2 years ago
In the adjoining figure, XY = XZ . YQ and ZP are the bisectors of <img src="https://tex.z-dn.net/?f=%20%5Cangle" id="TexFormula1
svetlana [45]

Answer:

See Below.

Step-by-step explanation:

Statements:                                              Reasons:

1)\, XY=XZ                                              Given

2) \text{ $ m\angle Y= m\angle Z$}                                        Isosceles Triangle Theorem

\displaystyle 3) \text{ $m\angle Y=m\angle XYQ + \angle QYZ$}                  Angle Addition

\displaystyle 4)\text{ $YQ$ bisects $\angle XYZ$}                               Given

5) \text{ $m\angle XYQ=m\angle QYZ$}                           Definition of Bisector

\displaystyle 6)\text{ $m\angle Y=2m\angle QYZ$}                               Substitution

7)\text{ $m\angle Z=m\angle XZP+m\angle PZY$}              Angle Addition

8)\text{ $ZP$ bisects $\angle XZY$}                              Given

\displaystyle 9) \text{ $m\angle XZP=m\angle PZY$ }                          Definition of Bisector

\displaystyle 10) \text{ $ m\angle Z = 2m\angle PZY $}                            Substitution

11)\text{ } 2m\angle QYZ=2m\angle PZY                    Substitution

12)\text{ }m\angle QYZ=m\angle PZY                        Division Property of Equality

13)\text{ } YZ=YZ                                         Reflexive Property

14)\text{ } \Delta YZP\cong\Delta ZYQ                             Angle-Side-Angle Congruence*

15)\text{ } YQ=ZP                                         CPCTC

*For clarification:

∠Y = ∠Z

YZ = YZ (or ZY)

∠PZY = ∠QYZ

So, Angle-Side-Angle Congruence:

ΔYZP is congruent to ΔZYQ

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