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ankoles [38]
3 years ago
9

The two triangles are similar.

Mathematics
1 answer:
alisha [4.7K]3 years ago
6 0
The answer to this is x = 5.

You might be interested in
45 POINTS Evaluate the limit as h goes to 0 of the quotient of the quantity the 4th power of 3 plus h minus 81 and h. SEE PICTUR
kow [346]

Answer:

108

Step-by-step explanation:

View Image.

Whenever you have a limit and the answer to that limit is one of the indeterminant form, you can use the L'Hopital's Rule to solve for the limit.

<u>Indeterminant forms:</u>

\frac{0}{0} , \frac{\infty}{\infty}, 0\cdot \infty, \infty - \infty, 0^{0}, \infty^{0}, 1^{\infty}

<u>L'Hopitals Rule:</u>

L'Hopitals rule is just taking the derivative of the numerator, and the derivative of the denominator separately.

After doing the L'Hopital's rule, take the limit again. If the result is an actual number then you got your answer.

If the result is another indeterminant form then use L'Hopitals rule again and check the limit again after that. Repeat the process until you get your answer.

5 0
3 years ago
How tall is the model? It's is #1.
Kazeer [188]
305.5 feet * .01 = 3.055 feet
4 0
3 years ago
Read 2 more answers
a campus contains 175 calories per 2.5 servings which of the following is not an equivalent number of calories per serving
Tcecarenko [31]
I think your answer is  <span>525</span>
7 0
3 years ago
Need help with this homework question
blondinia [14]
The question is not attach!
3 0
2 years ago
(−4 + 5) − (6 + 7) = x x 0
weeeeeb [17]

1

Add the numbers

(

−

4

+

5

)

−

(

6

+

7

)

=

0

({\color{#c92786}{-4}}+{\color{#c92786}{5}})-(6+7)=xx^{0}

(−4+5)−(6+7)=xx0

(

1

)

−

(

6

+

7

)

=

0

({\color{#c92786}{1}})-(6+7)=xx^{0}

(1)−(6+7)=xx0

2

Add the numbers

1

−

(

6

+

7

)

=

0

1-({\color{#c92786}{6}}+{\color{#c92786}{7}})=xx^{0}

1−(6+7)=xx0

1

−

(

1

3

)

=

0

1-({\color{#c92786}{13}})=xx^{0}

1−(13)=xx0

3

Multiply the numbers

1

−

1

⋅

1

3

=

0

1{\color{#c92786}{-1}} \cdot {\color{#c92786}{13}}=xx^{0}

1−1⋅13=xx0

1

−

1

3

=

0

1{\color{#c92786}{-13}}=xx^{0}

1−13=xx0

4

Subtract the numbers

1

−

1

3

=

0

{\color{#c92786}{1-13}}=xx^{0}

1−13=xx0

−

1

2

=

0

{\color{#c92786}{-12}}=xx^{0}

−12=xx0

5

Combine exponents

−

1

2

=

0

-12={\color{#c92786}{xx^{0}}}

−12=xx0

−

1

2

=

1

-12={\color{#c92786}{x^{1}}}

−12=x1

Show less

Solution

−

1

2

=

1

3 0
3 years ago
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