The two triangles are similar.

Please help!!!!!!!!!!

Gnoma [55]

Answer:

The surface of the prism is 84m²

Step-by-step explanation:

You have 4 figures here (two the same triangles)

you need to determine the surface of each and then sum it to one. This will be your final surface.

rectangles:

3*6= 18m²

5*6 = 30m²

4*6 = 24m²

triangles:

You need to determine the square of the triangles from the Heron's formula.

Heron's formula states that the area of a triangle whose sides have lengths a, b, and c is

$S=\sqrt{s(s-a)(s-b(s-c)}$ ,

where s is the semi-perimeter of the triangle; that is,

$s=\frac{a+b+c}{2}$ .

So the permimeter of the triangle is

2p=4+5+3 = 12m

p = 6m

$S = \sqrt{p*(p-a)*(p-b)*(p-c)} = \sqrt{6*(6-3)*(6-4)*(6-5)} = \sqrt{6*3*2*1} =\sqrt{36} =6[m^{2} ]$

So the surface of the prism is a total sum of all surfaces:

P = 18m²+30m²+ 24m²+2*6m² = 84m²

6 0

3 years ago

The probability of passing the math class of Professor Jones is 64%, the probability of passing Professor Smith's physics class

alexgriva [62]

Answer:

The probability of using one or the other is 36%

Step-by-step explanation:

For solving this problem it is easy if we see it in a ven diagram, for this first we are going to name the initial conditions with some variables:

Probability of passing Professor Jones math class = 64% =0,64

P(J) = 0.64

Probabiliry of passing Professor Smith's physics class = 32% =0.32

P(S) = 0.32

Probability of passing both is = 30% = 0.30

P(JnS) = 0.30 (Is is an intersection so it is in the middle of the ven diagram

We need to know which is the probability of pasing one or the other for this we need to take out the probability of passing both for this we have to add the probability of passing Professor Jones math class with the probabiliry of passing Professor Smith's physics class and substract the probability of passing both for each one:

P(JuS) = (P(J) - P(JnS)) + (P(S) - P(JnS)) = (0.64 - 0.30) + (0.32 - 0.30) = 0.34 + 0.02 = 0.36 = 36%

If you check the ven diagram you can see that if we add all what is in red we will have the probability of passing Professor Jones math class and if we add all what is in blue we wiill have the probability of passing Professor Smith's physics class, and if we add just what is in each corner we will get the same value that is the probabilty of passsing one or the other.