Answer:
Since the calculated value of Z does not fall in the critical region we accept our null hypothesis that mean = 60 seconds
Step-by-step explanation:
State the null hypothesis
H0: u = 60against the claim
Ha u≠ 60 (this is a two tailed test)
Sample size n= 36
Sample mean=X`= 55
Population mean = u= 60
The significance level α = 0.05
Standard deviation= Sd = 22 seconds
Z= X`- u / Sd /√n
Z= 55- 60 / 22/√6
z= - 5/22/6
Z= -1.3635
The value of z from the table is Z∝/2= ±1.96
The critical region is less than - 1.96 and greater than 1.96.
Since the calculated value of Z does not fall in the critical region we accept our null hypothesis that mean = 60 seconds
Answer: 1,045 passengers
Step-by-step explanation:
This question involves multiple steps. Let's first try to figure the number of children on the cruise.
The ratio of girls to the total number of children was 2:5. There are 198 boys.
This information tells me that for every 5 children, there's 2 girls and 3 boys.
Based off of this information, we can divide the total number of boys by 3 in order to find the number of children.
198÷3=66
Let's multiply 66 by 5 since that's the number of groupings based off the ratio.
66×5=330
Let's check the number of children. Since the ratio of girls to total children is 2:5 and we already confirmed there's 198 boys, there should be 132 girls. We can turn this ratio into a fraction where 2/5 of the children are girls. we can confirm this by multiply 330 by 2/5 (0.4) and getting 132.
There are 330 children on the cruise.
The ratio of the number of adults to the number of children was 13:6.
For every 6 children, there were 13 adults. Let's divide the number of children by 6 in order to find the number of groupings.
330÷6=55
Let's now multiply the groupings by 13 to find the number of adults.
55×13=715
So there should be 715 adults and 330 children on the cruise.
715+330=1,045
By common multiple method and division method
Your pay rate is $4.50/hour.
27/6=4.5=$4.50
8x - 3x - 7 = 23
5x - 7 = 23
5x = 30
x = 30/5 = 6
