It is basically 8 thousand plus one thousand two hundred so your answer would be 9200
Answer:
Step-by-step explanation:
In finding the COMMON DIFFERENCE, subtract the 2nd term and the first term.
a1 = -4
a2 = -2
Let "d" representing the COMMON DIFFERENCE.
d = -2 -(-4)
d = -2 + 4
d = 2
ANSWER:
THE COMMON DIFFERENCE OF THIS SEQUENCE IS 2
Answer:
A. -12 meters
B. 28 meters
C. 40 meters
Step-by-step explanation:
The surface of the ocean would be 0.
Taking this into account, 12 meters below would be 0 - 12, which is -12. Therefore A's elevation would be -12.
For the sea bird, 28 meters above the surface, which is again 0, would be 0 + 28. B's elevation is 28.
Since the fish is 12 meters below the surface and the sea bird is 28 meters above the surface, simply add the two numbers up to get a total of 40 meters. C would be 40 meters.
Answer:
i think its D dont fullly take my word tho
Step-by-step explanation:
Answer:
0.2364
Step-by-step explanation:
We will take
Lyme = L
HGE = H
P(L) = 16% = 0.16
P(H) = 10% = 0.10
P(L ∩ H) = 0.10 x p(L U H)
Using the addition theorem
P(L U H) = p(L) + P(H) - P(L ∩ H)
P(L U H) = 0.16 + 0.10 - 0.10 * p(L u H)
P(L U H) = 0.26 - 0.10p(L u H)
We collect like terms
P(L U H) + 0.10P(L U H) = 0.26
This can be rewritten as:
P(L U H)[1 +0.1] = 0.26
Then we have,
1.1p(L U H) = 0.26
We divide through by 1.1
P(L U H) = 0.26/1.1
= 0.2364
Therefore
P(L ∩ H) = 0.10 x 0.2364
The probability of tick also carrying lyme disease
P(L|H) = p(L ∩ H)/P(H)
= 0.1x0.2364/0.1
= 0.2364
