Answer:
540
Step-by-step explanation:
Volume of A = 1728
volume of B = 729
<span> (1728 / 729) = (a / b)^3 (a = width of A, b = width of B)
a / b = cube root (1728 / 729) = 4/3 </span><span> b = 10 (given)
a / 10 = 4/3 </span><span>
a = 40/3 = 13.33333</span>
so width of A is 13.33m
The event "Atleast once" is the complement of event "None".
So, the probability that Marvin teleports atleast once per day will the compliment of probability that he does not teleports during the day. Therefore, first we need to find the probability that Marvin does not teleports during the day.
At Morning, the probability that Marvin does not teleport = 2/3
Likewise, the probability tha Marvin does not teleport during evening is also 2/3.
Since the two events are independent i.e. his choice during morning is not affecting his choice during the evening, the probability that he does not teleports during the day will be the product of both individual probabilities.
So, the probability that Marvin does not teleport during the day = 
Probability that Marvin teleports atleast once during the day = 1 - Probability that Marvin does not teleport during the day.
Probability that Marvin teleports atleast once during the day = 
75/5-(4-1)^2
75 / 5 = 15
15-(4-1)^2
15-3^2
answer: 6
For each power of ten , the number of zeros written in the product is the same as the number of exponents.