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SIZIF [17.4K]
3 years ago
13

What is the value of AAA when we rewrite 4^{31x}4 31x 4, start superscript, 31, x, end superscript as A^{ x}A x A, start supersc

ript, x, end superscript
Mathematics
2 answers:
Yuri [45]3 years ago
7 0

Answer:

A = 4^31

Step-by-step explanation:

irina [24]3 years ago
5 0

Answer:

A = 4^{31}

Step-by-step explanation:

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A small rocket is fired from a launchpad 15 m above the ground with an initial velocity left angle 400,450,600 right angle ​m/s.
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Answer:

a)

v=<400, 450+3t, 600-9.81t> m/s

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b) attach file

c) t=122.324s

d) z=18369.9854 m

Step-by-step explanation:

a)

The equation for velocity of each component is v=v_{0}+at, in this case the x-axis component has acceleration 0\frac{m}{s^{2} }, the y-axis component has acceleration 3\frac{m}{s^{2} } and the z-axis component has -g\frac{m}{s^{2} }, where g=9.81\frac{m}{s^{2} }.

The equation for position of each component is  x=x_{0}+v_{0}t+at^{2}/2,

with <x_{0}, y_{0},z_{0}>=<0,0,15>.

c) This time is t when z=0, with positive sign.

d)Solving the equation V_f^{2}=V_o^2 + 2*a*(z-z_{0}) for z, with V_f=0.

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Answer:

a) 29.4-1.96\frac{7}{\sqrt{10}}=25.06  

29.4+1.96\frac{7}{\sqrt{10}}=33.74  

So on this case the 95% confidence interval would be given by (25.06;33.74)  

b) z=\frac{29,4-25}{\frac{7}{\sqrt{10}}}=1.988  

p_v =P(z>1.988)=0.0234    

If we compare the p value and the significance level given \alpha=Step-by-step explanation:Previous conceptsA confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  &#10;The margin of error is the range of values below and above the sample statistic in a confidence interval.  &#10;Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  &#10;Part a&#10;Data given: 30 30 42 35 22 33 31 29 19 23&#10;We can calculate the sample mean with the following formula:[tex] \bar X = \frac{\sum_{i=1}^n X_i}{n}= 29.4 the sample mean

\mu population mean (variable of interest)  

\sigma=7 represent the population standard deviation  

n=10 represent the sample size  

95% confidence interval  

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96  

Now we have everything in order to replace into formula (1):  

29.4-1.96\frac{7}{\sqrt{10}}=25.06  

29.4+1.96\frac{7}{\sqrt{10}}=33.74  

So on this case the 95% confidence interval would be given by (25.06;33.74)  

Part b

What are H0 and Ha for this study?  

Null hypothesis:  \mu \leq 25  

Alternative hypothesis :\mu>25  

Compute the test statistic

The statistic for this case is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

We can replace in formula (1) the info given like this:  

z=\frac{29,4-25}{\frac{7}{\sqrt{10}}}=1.988  

Give the appropriate conclusion for the test

Since is a one side right tailed test the p value would be:  

p_v =P(z>1.988)=0.0234  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis.    

8 0
3 years ago
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