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3 years ago

What is the rule for the reflection ?

Mathematics

1 answer:

ollegr [7]3 years ago

6 0

Answer:

$\large\boxed{r_{y-axis}\to(-x,\ y)}$

Step-by-step explanation:

Look at the picture.

A(-2, 1) → A'(2, 1)

B(-4, 1) → B'(4, 1)

(x, y) → (-x, y)

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Which is a factor of 2x^2- 12x- 14

lesya692 [45]

Answer:

Step-by-step explanation:

2x² - 12x - 14

2(x² - 6x - 7)

2(x² - 7x + x - 7)

2(x - 7)(x + 1)

4 0

3 years ago

Please tell the function equation as well too

Usimov [2.4K]

Answer:

A= Rate of change is y=4x, this is because it is set up as y/x and for the graph B= y=3x. Function A is greater in change than Function B because if you substitute x for 1, A would be 4 and B would be 3.

Step-by-step explanation:

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3 years ago

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Can someone help me with (2/3 +1/4) • 5/6

strojnjashka [21]

Answer:

35/6

Step-by-step explanation:

add the fractions in parentheses by finding the common denominaters and adding. then multiply your answer by 5/6. :)

4 0

3 years ago

Read 2 more answers

Efectuati calculele:

NNADVOKAT [17]

$\sqrt{(5 - 1)^{2}} + \sqrt{20}$

$\sqrt{4^{2}} + \sqrt{4 * 5}$

$\sqrt{16} + \sqrt{4} \sqrt{5} 
$

$4 + 2 \sqrt{5} 
$

$4\sqrt{5} + 2 \sqrt{5} 
$

$6 \sqrt{5}$

$\sqrt{(10 - 3)^{2}} + \sqrt{20 * 18}$

$\sqrt{7^{2}} + \sqrt{4 * 9 * 5 * 2}$

$\sqrt{49} + \sqrt{36 * 10}$

$7 + \sqrt{36}\sqrt{10}$

$7 + 6\sqrt{10}$

$7\sqrt{10} + 6\sqrt{10}$

$13\sqrt{10}$

$\sqrt[3]{(3 + 1)^{2}} - \sqrt{(3 - 2)x^{2}$

$\sqrt[3]{4^{2}} - \sqrt{x^{2}$

$\sqrt[3]{16} - x[tex] \\[tex] \sqrt[3]{8 * 2} - x$

$\sqrt[3]{8} \sqrt[3]{2} - x
$

$2\sqrt[3]{2} - x$

8 0

3 years ago

Which is not a step in finding the scale factor of dilation

mariarad [96]

1)To find a Scale factor of Dilation, about the origin

We have

Pre-mage Image

(x, y) k(x,y)

For example

Pre-image Image

(2,4) 2(2,4) = (4,8)

2)When it's not about the origin then we have to count from the Projection Point

Having said this, ex

Which is not a step

We can divide the x value of the image over the pre-image, not the way around.

In the example, I've given if we divide the pre-image over the image value we would have found a scale factor of 1/2. In the example, The scale factor was the inverse: 2

5 0

1 year ago