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saw5 [17]
2 years ago
8

In circle A below, chord BC and diameter DAE intersect at F. If arc CD = 46° and arc BE = 78°, what is m_BFE? D B А​

Mathematics
1 answer:
wel2 years ago
6 0

Given:

Consider the below figure attached with this question.

In circle A below, chord BC and diameter DAE intersect at F.

The arc CD = 46° and arc BE = 78°.

To find:

The measure of angle BFE.

Solution:

According to intersecting chords theorem, if two chords intersect inside the circle then the angle on the intersection is the average of intercepted arcs.

Using intersecting chords theorem, we get

m\angle BFE=\dfrac{1}{2}(m(arcCD)+m(arcBE))

m\angle BFE=\dfrac{1}{2}(46^\circ+78^\circ)

m\angle BFE=\dfrac{1}{2}(124^\circ)

m\angle BFE=62^\circ

Therefore, the measure of angle BFE is 62°.

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Solve for x and y:<br> 3/x -1/y =13/10<br> 1/x + 2/y =9/10
harkovskaia [24]

Answer:

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_____

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X^2 + 5x - 24 = 0 How do I solve by factoring
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