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2 years ago

If 3 + root8 by 3-root8 + 3-root8 by 3+root8 = a+broot2 find a and b

1 answer:

s2008m [1.1K]2 years ago

8 0

If $\frac{3+\sqrt{8} }{3-\sqrt{8} } +\frac{3-\sqrt{8} }{3+\sqrt{8} }=a+b\sqrt{2}$ , the value of a and b is given as a = 34 and b = 0

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables or numbers.

$\frac{3+\sqrt{8} }{3-\sqrt{8} } +\frac{3-\sqrt{8} }{3+\sqrt{8} }\\ \\\frac{9+6\sqrt{8}+8+9-6\sqrt{8}+8 }{(3-\sqrt{8} )(3+\sqrt{8} )} \\\\\frac{34}{9-8} =34+0\sqrt{2}$

If $\frac{3+\sqrt{8} }{3-\sqrt{8} } +\frac{3-\sqrt{8} }{3+\sqrt{8} }=a+b\sqrt{2}$ , the value of a and b is given as a = 34 and b = 0

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Two urns contain white balls and yellow balls. The first urn contains 7 white balls and 7 yellow balls and the second urn contai

cestrela7 [59]

To find the probability that both balls are white you will find the probability of getting a while ball from each situation separately and then multiply these probabilities together.

1. 7/14 or 1/2 chance
2. 3/9 or 1/3 change

1/2 x 1/3 = 1/6

You will have a 1 in 6 chance of getting a white ball from both urns.

7 0

3 years ago

Simplify. x^3 ÷ x^5

fomenos

Answer:

x^-2

Step-by-step explanation:

(x*x*x)/(x*x*x*x*x)

1/x*x

1/x^2

x^-2

3 0

3 years ago

Read 2 more answers

Help me with number 15 and 16

loris [4]

Answer:

Problem 15)

$40.91

Problem 16)

12.446 cm^2

Step-by-step explanation:

Problem 15)

Gala.

12.8 * 1.35 = 17.28

Honeycrisp.

9 * 1.68 = 15.12

Fuji

7.4 * 1.15 = 8.51

17.28 + 15.12 + 8.51 = 40.91

Problem 16)

(area1) + (area2) + (area3) = (total area)

(1.25*4.38) + (1.36*2.15) + (1.14*3.55) = x

5.475 + 2.924 + 4.047 = x

12.446 = x

3 0

3 years ago

A rectangular yard measuring 39 ft by 67 ft is bordered (and surrounded) by a fence. Inside, a walk that is 4 ft wide goes all t

Gekata [30.6K]

The area of the walk is 784 square feet

Area is the quantity that expresses the extent of a region on the plane or on a curved surface

First, calculate the area of the rectangular yard.

Area = L x W

where A equals area, L equals length, and W equals width.

According to the stated problem:

A = 39 x 67

A = 2613 square feet <-------Area of Rectangular yard.

Now, according to the stated problem there is a walk that is 4 feet wide going all the way along the fence (Inside). "

Therefore, we have 8 feet to subtract from each of the values above (39) and (67).

That is 4 feet on each side,

A = L x W

A = 31 x 59

A = 1829 square feet <----------Area of new rectangle formed by allowing for three foot walk.

Now, subtract the area of the new rectangle formed from the area of the original area. Doing so, will give you the area of the walk, correct?

Original area = 2613 square feet

New area = 1829 square feet

Hence, the Area of WALK = 784 square feet

Learn more about area on: brainly.com/question/22972014

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3 0

1 year ago

Segment PH is graphed on the coordinate grid where P is (-31,8) and H is (29,-10). Point E is the midpoint of segment PH. If poi

maks197457 [2]

Answer:

The coordinates of point A are (-11 , 2)

Step-by-step explanation:

- The coordinates of point P are (-31 , 8)

- The coordinates of point H are (29 , -10)

- Point E is the mid-point of segment PH

- The coordinates of the the mid-point are:

→ $x=\frac{x_{1}+x_{2}}{2}$ and $y=\frac{y_{1}+y_{2}}{2}$

∵ E is the mid-point of segment PH

∴ The x-coordinate of point E is $x=\frac{-31+29}{2}=-1$

∴ The x-coordinate of point E is -1

∴ The y-coordinate of point E is $y=\frac{8+-10}{2}=-1$

∴ The y-coordinate of point E is -1

∴ The coordinates of point E are (-1 , -1)

- Point A is graphed $\frac{2}{3}$ of the way along the segment from P to E

- That mean the distances from points P to A is 2 parts and from P to E

is 3 parts, then the distance from A to E is "3 - 2" = 1 part

- So point A divides the line segment PE at ratio 2 : 1 from P

- The coordinates of the division point are:

→ $x=\frac{x_{1}m_{2}+x_{2}m_{1}}{m_{1}+m_{2}}$ and $y=\frac{y_{1}m_{2}+y_{2}m_{1}}{m_{1}+m_{2}}$

∵ Point A divides PE at ratio 2 : 1

∵ The coordinates of point P are (-31 , 8)

∵ The coordinates of point E are (-1 , -1)

∴ The x-coordinate of point A is $x=\frac{(-31)(1)+(-1)(2)}{2+1}= -11$

∴ The x-coordinate of point A is -11

∴ The y-coordinate of point A is $x=\frac{(8)(1)+(-1)(2)}{2+1}=2$

∴ The y-coordinate of point A is 2

∴ The coordinates of point A are (-11 , 2)

* The coordinates of point A are (-11 , 2)

3 0

3 years ago