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34kurt
2 years ago
15

If 3 + root8 by 3-root8 + 3-root8 by 3+root8 = a+broot2 find a and b

Mathematics
1 answer:
s2008m [1.1K]2 years ago
8 0

If \frac{3+\sqrt{8} }{3-\sqrt{8} } +\frac{3-\sqrt{8} }{3+\sqrt{8} }=a+b\sqrt{2}, the value of a and b is given as a = 34 and b = 0

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables or numbers.

\frac{3+\sqrt{8} }{3-\sqrt{8} } +\frac{3-\sqrt{8} }{3+\sqrt{8} }\\ \\\frac{9+6\sqrt{8}+8+9-6\sqrt{8}+8  }{(3-\sqrt{8} )(3+\sqrt{8} )} \\\\\frac{34}{9-8} =34+0\sqrt{2}

If \frac{3+\sqrt{8} }{3-\sqrt{8} } +\frac{3-\sqrt{8} }{3+\sqrt{8} }=a+b\sqrt{2}, the value of a and b is given as a = 34 and b = 0

Find out more on equation at: brainly.com/question/2972832

#SPJ1

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In this problem, there are two congruent right triangles: triangle XCA and triangle XBC, where the hypotenuse are XA and XB respectively. Considering triangle XBC, XB = radius = 17, and BC = 30 / 2 = 15. By pythagorean theorem, XC = sqrt(17^2 - 15^2) = sqrt(289 - 225) = sqrt(64) = 8 units.

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A veterinarian treated 7 dogs this morning. The list below gives the weights (in pounds) of each dog.
Fantom [35]
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3 years ago
Suppose the voltage in an electrical circuit varies with time according to the formula V(t) = 40 sin(t) for t in the interval [0
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The numerical value of the mean voltage is 25.47 V

To find the numerical value of the mean voltage, V of V(t) = 40 sin(t), we integrate V(t) with respect to t over the interval [0.π]

So,

V = \frac{1}{\pi } \int\limits^\pi _0 {V(t)} \, dt \\V = \frac{1}{\pi } \int\limits^\pi _0 {40sint} \, dt \\V = \frac{1}{\pi } [-40cost]_{0}{\pi }  \\V = \frac{1}{\pi } -[40cos\pi  - 40cos0]\\\\V = \frac{1}{\pi } (-[40 X (-1) - 40 X 1})\\V = -\frac{1}{\pi } [-40 - 40]\\V = \frac{80}{\pi } \\V = 25.465 V

V ≅ 25.47 V

So, the numerical value of the mean voltage is 25.47 V

Learn more about mean volatage here:

brainly.com/question/17928028

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Answer:

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Step-by-step explanation:

<u>Use intersecting chords theorem:</u>

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