Answer:
The WIP limit is 0.50 days.
Step-by-step explanation:
The Computation of WIP limits:
to begin with, it is required to compute the process and procedure efficiency which will be computed as follows:
Value Added Time = 12 days (arriving time)
Non-Value-Added Time = 12 days (departure time)
Efficiency = Value Added / (Value Added + Non-Value Added)
= 12 / (12+12)
= 12 / 24
= 0.50 or 50%
the most obligatory throughput time will be 0.25 days to realize the profits
WIP limit = Throughput time / Efficiency
= 0.25 / 50%
= 0.50 days.
The WIP limit is 0.50 days.
Answer:
the area is 15
Step-by-step explanation:
if you split this shape into a triangle and a square, the triangle would measure with a legnth og 4 and a with of 3, which = 12 and then you divide by 2 to = the triangles area(6) then you add tht to the area of the square 3*3=9. so the answer would be 15
Answer:
0
Step-by-step explanation:
When given 3 triangle sides, to determine if the triangle is acute, right or obtuse:
1) Square all 3 sides.
4, 3, 4,
16, 9, 16
2) Sum the squares of the 2 shortest sides.
16 + 9 = 25
3) Compare this sum to the square of the 3rd side.
25 > 16
if sum > 3rd side² Acute Triangle
So, it is an acute triangle.
Source:
http://www.1728.org/triantest.htm
Roots with imaginary parts always occur in conjugate pairs. Three of the four roots are known and they are all real, which means the fourth root must also be real.
Because we know 3 and -1 (multiplicity 2) are both roots, the last root 
is such that we can write
There are a few ways we can go about finding , but the easiest way would be to consider only the constant term in the expansion of the right hand side. We don't have to actually compute the expansion, because we know by properties of multiplication that the constant term will be 
.
Meanwhile, on the left hand side, we see the constant term is supposed to be 9, which means we have
so the missing root is 3.
Other things we could have tried that spring to mind:
- three rounds of division, dividing the quartic polynomial by 
, then by 
twice, and noting that the remainder upon each division should be 0
- rational root theorem
