$\text{Given that the distance from Jim's house to the intersection of Thornwood drive}\\
\text{and Holly Drive is given by the expression }(15x-7)\\
\\
\text{And the total distance from Jim's house to Adam's house when traveled on}\\
\text{Thornwood Drive and Holly Drive is given by the expression }(23x-2)$

$\text{so the distance from Adam's house to the intersection of Thornwood Drive }\\
\text{and Holly Drive will be given by the difference of the total distance from Jim's }\\
\text{house to the Adam's house and the distance from Jim's house to the intersection.}\\
\\
\text{Hence the distance from Adam's house to the intersection of Thornwood Drive}$

$\text{and Holly Drive is}=(23x-2)-(15x-7)\\
\\
=23x-2-15x+7\\
\\
=8x+5$

Hence the expression that represents the distance from Adam's house to the intersection of Thornwood Drive and Holly Drive is: 8x+5

8 0

3 years ago

Read 2 more answers

ollegr [7]

Answer:

3z(5z-3)

Step-by-step explanation:

first you choose the common items which in this case was 3z the you divide 15 by 3 and 9 by 3

4 0

3 years ago