Just add a similar triangle from the opposite side
Then what happens
- Hypotenuse of this triangle becomes common and diagonal of the rectangle.
Now
- Length=L=5
- Breadth=B=4
Area
- Area of triangle=20/2=10units^2
Does anyone know this ?
1 answer:
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To determine which of the rectangles has a different area, the areas of the four rectangles must be calculated. The rectangle with a different area is rectangle b
The dimension of the 4 rectangles are:
a. length: 4x and width: 4
b. length: 11 and width: x
c. length: 2 and width: 8x
d. length: 16x and width: 1
The area of a rectangle is:
<u>Rectangle (a)</u>
<u>Rectangle (b)</u>
<u>Rectangle (c)</u>
<u>Rectangle (d)</u>
Rectangles (a), (c) and (d) have the same area (i.e. 16x) while rectangle (b) has 11x as its area.
Hence, the rectangle with a different area is rectangle (b).
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