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patriot [66]
3 years ago
14

A coffee supply store waits until the orders for its special blend reach 100 pounds before making up a batch. Columbian coffee s

elling for $8.85 a pound is blended with Brazilian coffee selling for $3.85 a pound to make a product that sells for $6.55 a pound. How much of each type of coffee should be used to make the blend that will fill the orders?
Mathematics
1 answer:
yan [13]3 years ago
5 0
X - Columbian coffee ( in pounds),
y - Brazilian coffee ( in pounds );
x + y = 100
8.85 x + 3.85 y = 6.55 ( x + y )
----------------------------------------
x = 100 - y
8.85 ( 100 - y ) + 3.85 y = 6.55 * 100
855 - 8.55 y + 3.85 y = 655
- 5 y = - 230
y = ( - 230 ) : ( - 5 )
y = 46
x = 100 - 46
x = 54
Answer: 54 pounds of Columbian coffee and 46 pounds of Brazilian coffee should be used.
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Answer:

We conclude that:

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Step-by-step explanation:

Given the expression

\left(5p^3\right)\:\left(-1m^8p^2\right)

Apply the rule:

a\left(-b\right)=-ab

so the expression becomes

\left(5p^3\right)\left(-1\cdot \:m^8p^2\right)=-5p^3\cdot \:1\cdot \:m^8p^2

Apply the rule:

a^b\cdot \:a^c=a^{b+c}

so the expression becomes

                             =-5p^{3+2}\cdot \:1\cdot \:m^8         ∵ p^3p^2=p^{3+2}

                             =-5p^5\cdot \:1\cdot \:m^8

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Therefore, we conclude that:

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olga2289 [7]
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