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vovangra [49]
3 years ago
10

Can you help me with Math

Mathematics
2 answers:
Nonamiya [84]3 years ago
8 0

Answer:

42+106=x

148=x

Step-by-step explanation:

sattari [20]3 years ago
8 0
Answer would be x= 148 i think
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Consider these functions
vitfil [10]

9514 1404 393

Answer:

  C.  3x² +24

Step-by-step explanation:

Use the given function definitions and simplify.

  g(f(x))=g\left(\dfrac{1}{3}x^2+4\right)\\\\=9\left(\dfrac{1}{3}x^2+4\right)-12\\\\=3x^2+36-12\\\\\boxed{g(f(x))=3x^2+24}\qquad\textbf{matches C}

5 0
3 years ago
15 points please help
Sonja [21]

Answer: sorry dont know this

Step-by-step explanation:

5 0
3 years ago
5. Solve the problem by writing an inequality. A club decides to sell T-shirts for $12 as a fund-raiser. It costs $20 plus $8 pe
kykrilka [37]
T=the amount of shirts
12t-20-8t=100
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8 0
3 years ago
If the producer in a food chain has 1000 kcal of energy available, how much energy would each of the consumers have?
madam [21]

Answer:

Primary consumer = 100kcal

Secondary consumer = 10kcal

Tertiary consumer = 1kcal

Step-by-step explanation:

In a food chain, transfer of energy occurs when one organism feeds on another organism. However, only 10% of energy is transferred from one organism to another because energy is lost as heat when the organisms perform metabolism.

In a typical food chain consisting of a producer, a primary (1st), secondary (2nd) and tertiary (3rd) consumer, if there are 1000 kcal of energy available in the producer, then:

- Primary consumer will obtain; 10% of 1000Kcal

10/100 × 1000

Primary consumer = 100kcal of energy.

- Secondary consumer will obtain as follows; 10% of 100kcal available energy

= 10/100 × 100

Secondary consumer = 10Kcal of energy.

- Tertiary consumer will obtain as follows; 10% of 10Kcal of available energy.

= 10/100 × 10

Tertiary consumer = 1 kcal of energy.

6 0
3 years ago
What is a Geometric series
IRISSAK [1]

Answer:

Step-by-step explanation:

Series having the constant ratio between any term and its preceding one.

5 0
4 years ago
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