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Yuliya22 [10]
3 years ago
8

Match each inequality to the number line that represents its solution

Mathematics
2 answers:
Inessa05 [86]3 years ago
8 0

We have to establish a feature that gives us the first answer. When going with a number line and plotting with a ≤ or ≥ symbol, the point will be closed or black and when going with a < or > symbol, the point will be opened or white. So we can safely say that 75 < 69-x is the 3rd one. So now when solving an inequality, you just have to move the number on the side of X to the other one and to do that, we have to do the opposite value that it has. (ex. 130+x > 50= x > -80, we subtracted) So we apply that to every inequality and find where we need to put them in. That gives us the answers of 150 + x ≤ 144 is the 4th one, x-51 ≤ -43 is the 1st one, and x-99 ≤ -104 is the 2nd one.

vlada-n [284]3 years ago
3 0

the first one that is x-99....... goes to the second answer box

the second that is x-51......... goes to the first answer box

the third that is 150+x......... goes to the fourth answer box

the fourth that is 69-x......... goes to the third answer box

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3 years ago
2(x-6)+5=-5<br>75=27+3(3t-2)<br>-2/3(6c-9)+x=-18
anyanavicka [17]

Answer:

{c = 25/4

{t = 6

{x = 1

Step-by-step explanation:

Solve the following system:

{2 (x - 6) + 5 = -5 | (equation 1)

{75 = 3 (3 t - 2) + 27 | (equation 2)

{x - 2/3 (6 c - 9) = -18 | (equation 3)

Express the system in standard form:

{0 c+0 t+2 x = 2 | (equation 1)

{0 c - 9 t+0 x = -54 | (equation 2)

{-(4 c) + 0 t+x = -24 | (equation 3)

Swap equation 1 with equation 3:

{-(4 c) + 0 t+x = -24 | (equation 1)

{0 c - 9 t+0 x = -54 | (equation 2)

0 c+0 t+2 x = 2 | (equation 3)

Divide equation 2 by -9:

{-(4 c) + 0 t+x = -24 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+2 x = 2 | (equation 3)

Divide equation 3 by 2:

{-(4 c) + 0 t+x = -24 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+x = 1 | (equation 3)

Subtract equation 3 from equation 1:

{-(4 c)+0 t+0 x = -25 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+x = 1 | (equation 3)

Divide equation 1 by -4:

{c+0 t+0 x = 25/4 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+x = 1 | (equation 3)

Collect results:

Answer: {c = 25/4

{t = 6

{x = 1

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3 years ago
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ExtremeBDS [4]

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Step-by-step explanation:

3 0
3 years ago
Several years ago, the mean height of women 20 years of age or older was 63.7 inches. Suppose that a random sample of 45 women w
Karo-lina-s [1.5K]

Answer:

1. C) H0: u = 63.7 in. versus H1: u > 63.7 in.

2. B). There is a 0.18 probability of obtaining a sample mean height of exactly 64.2 inches from a population whose mean height is 63.7 inches.

3. B) Reject the null hypothesis. There is sufficient evidence to conclude that the mean height of women 20 years of age or older is greater today.

Step-by-step explanation:

1. C) H0: u = 63.7 in. versus H1: u > 63.7 in.

the null hypothesis state that over the years the mean height is 63.7in. the alternative hypothesis will be if the mean height is greater than 63.7

2. z = (variate - mean)/ (standard deviation/\sqrt{N}

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meaning there is

B. There is a 0.18 probability of obtaining a sample mean height of exactly 64.2 inches from a population whose mean height is 63.7 inches.

3. if the level of significance is 0.05 or between  0.05 and 0.01, i.e. the confidence level is 95% or  between 95% and 99%, the results are considered  to be probably significant, i.e. the results  are probably correct,

therefore, the alternative hypothesis is correct

B) Reject the null hypothesis. There is sufficient evidence to conclude that the mean height of women 20 years of age or older is greater today.

8 0
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Answer:

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Step-by-step explanation:

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