<u>Answer:</u> The amount of heat needed is 29000 Cal.
<u>Explanation:</u>
The process involved in this problem are:
Now, we calculate the amount of heat released or absorbed in all the processes.
where,
= amount of heat absorbed = ?
m = mass of ice = 200 g
= final temperature =
= initial temperature =
Putting all the values in above equation, we get:
where,
= amount of heat absorbed = ?
m = mass of water or ice = 200 g
= latent heat of fusion = 80 Cal/g
Putting all the values in above equation, we get:
where,
= amount of heat absorbed = ?
m = mass of water = 200 g
= final temperature =
= initial temperature =
Putting all the values in above equation, we get:
Calculating the total heat absorbed, we get:
Hence, the amount of heat needed is 29000 Cal.