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elena55 [62]
2 years ago
13

A construction worker moved a crate full of equipment 15,0 m using a constant force

Physics
1 answer:
Mkey [24]2 years ago
7 0

Considering the definition of work and power, 157.5 W of power was developed.  

<h3>Power</h3>

Power is defined as how fast work is done. That is, power is the amount of work done per unit of time:

Power=\frac{work}{time}

P is the power developed by the force that performs the work and its unit of measurement in the International System is Watts (W).

The unit of measurement of work in the International System is the Joule (J). The time during which the work is developed has the unit of measurement in the International System of seconds (s).

<h3>Work </h3>

On the other side, work is defined as the force that is applied on a body to move it from one point to another.  

When a net force is applied to the body or a system and this produces displacement, then that force is said to perform mechanical work. This work can be positive if the system gains energy or negative if the system loses energy.

The work is equal to the product of the force by the distance and by the cosine of the angle that exists between the direction of the force and the direction that travels the point or the object that moves.

<h3>This case </h3>

In this case, the angle between the force and the displacement is 0 degrees. This is because the force and the displacement are in the same direction and sense, in the horizontal direction. So the cosine of 0 degrees will have a value of 1. Then work is equal to:

Work= force× distance

Being the force 105 N and the distance 15 meters, the work can be calculated as:

Work= 105 N× 15 meters

Solving:

<u><em>Work=  1,575 J</em></u>

Finally, being the time 10 seconds, the power can be calculated as:

Power=\frac{1,575 J}{10 s}

Solving:

Power= 157.5 W

In summary, 157.5 W of power was developed.  

Learn more about power and work:

<u>brainly.com/question/6763771</u>

<u>brainly.com/question/866077?referrer=searchResults</u>

brainly.com/question/14435134?referrer=searchResults

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Determine the frequency of the 2nd harmonic of a spring that has a 3rd harmonic resonance of f3=512 Hz.
Elena L [17]

Answer:

1) 341 Hz

Explanation:

When a string vibrates, it can vibrate with different frequencies, corresponding to different modes of oscillations.

The fundamental frequency is the lowest possible frequency at which the string can vibrate: this occurs when the string oscillate in one segment only.

If the string oscillates in n segments, we say that it is the n-th mode of vibration, or n-th harmonic.

The frequency of the n-th harmonic is given by

f_n = nf_1

where

n is the number of the harmonic

f_1 is the fundamental frequency

Here we have:

f_3=512 Hz is the frequency of the 3rd harmonic

So the fundamental frequency is

f_1=\frac{f_3}{3}=\frac{512}{3}=170.7 Hz

And so, the frequency of the 2nd harmonic is:

f_2=2f_1=2(170.7)=341.3 Hz

3 0
4 years ago
A person jumps from the roof of a house 3.5-m high. When he strikes the ground below, he bends his knees so that his torso decel
Korvikt [17]

The force exerted on his torso by his legs during the deceleration is 4365 N.

<u>Explanation:</u>

Mass of the torso m=45kg

Height of the building s=3.5 m

Decelerating distance=0.71 m

when he jumps to the ground, the only acceleration is acceleration due to gravity g

<u>motion1 from top to ground </u>

initial velocity u=0

we have to calculate final velocity v using the following equation of motion.

v^2-u^2=2gs\\v^2-0^2=2\times 9.8\times3.5=68.6\\v=\sqrt{68.6} \\=8.3

use height of the building as the distance s as the jump from top to the ground is only described here.

<u>Motion 2 on the ground</u>

v=0

u=8.3(final  velocity of motion 1)

The deceleration after striking the ground can  be calculated from the equation of motion

v^2-u^2=2as\\\\a=v^2-u^2/2\times 0.71\\=0^2-8.3^2/0.71=97 m/s^2

The decelerating distance is used in the place of s since since the motion after hitting the ground is described in this case.

The equation of force is

F=ma\\=45\times 97=4365 N

6 0
3 years ago
Find the velocity of a truck traveling north 50m in 20 seconds.
xz_007 [3.2K]

Answer:

2.5 m/s north

Explanation:

I took the test

3 0
3 years ago
Which of the following is an element?
Sergeeva-Olga [200]
Oxygen is on the Periodic Table of Elements as a member of the chalcogen group. It is a chemical element represented by the symbol O.

B would've also been a right answer if it weren't for the Dioxide part.

But the answer is C. Oxygen.
3 0
3 years ago
Which of the following are examples of a force? (choose as many as apply)
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All except B are examples of force
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