Answer: Conjecture: There is no triangle with side lengths N, 2N, and 3N (where N is a positive real number)
Proof:
We prove this by contradiction: Suppose there was an N for which we can construct a triangle with side lengths N, 2N, and 3N. We then apply the triangle inequalities tests. It must hold that:
N + 2N > 3N
3N > 3N
3 > 3
which is False, for any value of N. This means that the original choice of N is not possible. Since the inequality is False for any value of N, there cannot be any triangle with the given side lengths, thus proving our conjecture.
Answer:
Start
Percentage with triazine resistance- 57.6%
Percentage without triazine resistance- 42.4%
End
Percentage with triazine resistance- 78%
Percentage without triazine resistance- 22%
Step-by-step explanation:
Answer:
x=3/4
Step-by-step explanation:
Set up an equation:
1/6+x=1 2/3-x
1/6+x=5/3-x
1/6+x=10/6-x
2x=9/6
2x=3/2
4x=3
x=3/4
Check:
common denominator of 12
2/12+9/12=11/12 AND 20/12-9/12=11/12
125,000 because you would round it up
A=pie×radius squared is the area formula of a circle. The circumference formula or a circle is C=pie×diameter. 615.75=(3.14)(radius) squared. Divide both sides by the 3.14. What ever 615.75 divided by 3.14 is-is radius squared. The square root is your radius. The radius is half the diameter, so double what you have right now as the radius to get the diameter. Now since C=pie×diameter, your circumference is your pie×your diameter. Whatever your answer is-is your circumference.