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Nat2105 [25]
3 years ago
13

A bag contains the letters from the words SUMMER VACATION. You randomly choose a letter A, and do not replace it. Then you choos

e another letter A. What is the probability that both letters are A’s? Write your answer as a percent, with the percent symbol. If needed, round to the nearest tenth.
SHOW YOUR WORK:
Mathematics
1 answer:
ss7ja [257]3 years ago
7 0
<h3>Hello there i hope you are having a good day :) Your question : A bag contains the letters from the words SUMMER VACATION. You randomly choose a letter A, and do not replace it. Then you choose another letter A. What is the probability that both letters are A’s? Write your answer as a percent, with the percent symbol. If needed, round to the nearest tenth. </h3><h3>Firstly the word is SUMMER VACATION there are 14 letters in this word and 2 of them with the letter A So this would be 2/14 and 1/7 Then there is 13 letters because we used one already so it would be 1/13 Then the second A would equal 1/13 and this would be 1/7 and 1/13 you would times both given 1/91 now written that in percent with a percent symbol 1.0989011% So this would be 1.91%</h3><h3>Hopefully that helps you ❤</h3>

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How many integers in the set {n ∈ Z | 1 ≤ n ≤ 700} are divisible by 2 or 7?
sukhopar [10]
\large\begin{array}{l}\\\\ \textsf{This question gives us a set}\\\\ \mathsf{S=\{n \in\mathbb{Z}:~1\le n\le 700\}}\\\\ \mathsf{S=\{1,\,2,\,3,\,\ldots,\,699,\,700\}}\\\\\\ \bullet~~\textsf{Set of integers that are divible by 2 (even integers):}\\\\ \mathsf{A=\{n\in \mathbb{Z}:~n=2k,\,k\in\mathbb{Z}\}}\\\\ \mathsf{A=\{\ldots,\,-4,\,-2,\,0,\,2,\,4,\,\ldots\}}\\\\\\ \bullet~~\textsf{Set of integers that are divible by 7:}\\\\ \mathsf{B=\{n\in \mathbb{Z}:~n=7k,\,k\in\mathbb{Z}\}}\\\\ \mathsf{A=\{\ldots,\,-14,\,-7,\,0,\,7,\,14,\,\ldots\}} \end{array}

___________


\large\begin{array}{l}\\\\ \textsf{We want to know how many elements there are in the}\\\textsf{following set:}\\\\ \mathsf{S\cap (A\cup B)=(S\cap A)\cup(S\cap B)\qquad(i)} \end{array}

____________

\large\begin{array}{l}\\\\ \bullet~~\mathsf{S\cap A=\{n\in\mathbb{N}:~n=2k~~and~~1\le n\le 700,\,k\in\mathbb{Z}\}}\\\\ \mathsf{S\cap A=\{2,\,4,\,6,\,\ldots,\,698,\,700\}}\\\\ \mathsf{S\cap A=\{1\cdot 2,\,2\cdot 2,\,3\cdot 2,\,\ldots,\,349\cdot 2,\,350\cdot 2\}}\\\\\\ \textsf{So, there are 350 elements in }\mathsf{S\cap A:}\\\\ \mathsf{\#(S\cap A)=350.} \\\\\\ \bullet~~\mathsf{S\cap B=\{n\in\mathbb{N}:~n=7k~~and~~1\le n\le 700,\,k\in\mathbb{Z}\}}\\\\ \mathsf{S\cap B=\{7,\,14,\,21,\,\ldots,\,693,\,700\}}\\\\ \mathsf{S\cap B=\{1\cdot 7,\,2\cdot 7,\,3\cdot 7,\,\ldots,\,99\cdot 7,\,100\cdot 7\}} \\\\\\ \textsf{So, there are 100 elements in }\mathsf{S\cap B:}\\\\ \mathsf{\#(S\cap B)=100.} \end{array}

____________


\large\begin{array}{l}\\\\ \textsf{Therefore,}\\\\ \mathsf{\#\big[S\cap (A\cup B)\big]}\\\\ =\mathsf{\#\big[(S\cap A)\cup(S\cap B)\big]}\\\\ =\mathsf{\#(S\cap A)+\#(S\cap B)-\#\big[(S\cap A)\cap(S\cap B)\big]}\\\\ =\mathsf{350+100-50}\\\\ =\mathsf{450-50}\\\\ =\mathsf{400~elements.}\\\\\\ \textsf{There are 400 integers in S that are divisible by 2 or 7.} \end{array}


If you're having problems understanding the answer, try to see it through your browser: brainly.com/question/2105863


\large\begin{array}{l}\\\\ \textsf{Any doubts? Please, comment below.}\\\\\\ \textsf{Best wishes! :-)} \end{array}


Tags: <em>set theory divibilility divisible integers union intersection</em>

3 0
3 years ago
Can someone please help me I really need help help me thank you
harkovskaia [24]

Answer:

<h2><em><u>A to C = 25 </u></em></h2><h2><em><u>A to B = 13 </u></em></h2><h2><em><u>C to B = 37 </u></em></h2><h2><em><u></u></em></h2>

Step-by-Step Explanation:

<em><u>Perimeter</u></em> = 75

<em><u>Sides:</u></em>

2x + 3

3x + 4

2x - 9

<h2 /><h2><em><u>1. Equal the sides added together to the perimeter</u></em></h2>

75 = 2x + 3 + 3x + 4 + 2x - 9

<h2><em><u>2. Simplify Like terms</u></em></h2>

2x + 3 + 3x + 4 + 2x - 9  = 7x - 2

<h2><em><u>3. Place the equation back together</u></em></h2>

75 = 7x - 2

<h2><em><u>4. Isolate the variables and numbers</u></em></h2>

75 = 7x - 2

+2        +2

77 = 7x

<h2><em><u>5. Simplify the equation</u></em></h2>

77 = 7x

/7     /7

<h2><em><u>11 = x </u></em></h2>

<h2><em><u>6. Substitute the value of x into the side lengths.</u></em></h2>

2x + 3 = 2(11) + 3 = 22 + 3 = <em><u>25</u></em>

3x + 4 = 3(11) + 4 = 33 + 4 = <em><u>37</u></em>

2x - 9 = 2(11) - 9 = 22 - 9 = <em><u>13</u></em>

5 0
3 years ago
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