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S_A_V [24]
3 years ago
12

Lacey baked 20 cookies with 2 scoops of flour. With 5 scoops of flour, how many cookies can Lacey bake? Assume the relationship

is directly proportional.
Mathematics
1 answer:
Komok [63]3 years ago
6 0

Answer:

The number of cookies baked is 50

Step-by-step explanation:

Given as:

Lacey baked 20 cookies with 2 scoops of flour

∵ For 2 scoops of flour , The number of cookies baked is 20

so,For 1 scoops of flour , The number of cookies baked is \frac{20}{2}

∴ For 5 scoops of flour , The number of cookies baked is  \frac{20}{2} × 5

I.e Number of baked cookies = 10 × 5 = 50

Hence The number of cookies baked is 50  Answer  

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Answer:

Option: A is correct.

A) a part of a line that has one endpoint and extends indefinitely in one direction

Step-by-step explanation:

" A ray is a line that starts at a given point and goes off for ever in some direction. It may pass through another point as it does so "

Hence, option A is correct.

( The definition of Ray is:

A) a part of a line that has one endpoint and extends indefinitely in one direction )

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3 years ago
Which equation represents a line perpendicular to the line shown on the graph?
Vadim26 [7]

Answer:

See description below.

Step-by-step explanation:

To choose the correct equation, find the slope of the line on the graph. Identify two points on the line. Then subtract to find their rate of change using the slope formula.

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When you know the slope, find the negative reciprocal. For example, if the slope is 2/1 then the negative reciprocal is -1/2. This is the slope of a perpendicular line to a line with slope 2. Choose the equation which has this same slope.

Example:

y = 2x -1

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3 years ago
How do you simplify this?<br>x²y+xy² / y²+2/5 × xy​​​
polet [3.4K]

\huge \boxed{\mathbb{QUESTION} \downarrow}

  • How do you simplify this?
  • x²y+xy² / y²+2/5 × xy

\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}

\sf\frac{  { x  }^{ 2  }  y+x { y  }^{ 2  }    }{  { y  }^{ 2  }  + \frac{ 2  }{ 5  }   \times  xy  } \\

Factor the expressions that are not already factored.

_____

<u>How </u><u>to</u><u> factorise</u><u> </u><u>:</u><u>-</u>

<u>NUMERATOR</u> \downarrow

\sf \: x ^ { 2 } y + x y ^ { 2 }

Factor out xy.

\sf \: xy\left(x+y\right)

<u>DENOMINATOR</u> \downarrow

\sf{ y  }^{ 2  }  + \frac{ 2  }{ 5  }   \times  xy \\

Factor out 1/5.

\sf \: {\frac{1}{5}y\left(2x+5y\right)}  \\

_____

Continuing...

\sf\frac{xy\left(x+y\right)}{\frac{1}{5}y\left(2x+5y\right)}  \\

Cancel out y in both the numerator and denominator.

\sf\frac{x\left(x+y\right)}{\frac{1}{5}\left(2x+5y\right)}  \\

Expand the expression.

\sf\frac{x^{2}+xy}{\frac{2}{5}x+y}  \\

This can further simplified to as \downarrow

=    \boxed{\boxed{\bf\frac{5x\left(x  +y\right)}{2x+5y}}}

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