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tatiyna
4 years ago
15

What is 2x^2+7x-4/x^3 -1

Mathematics
2 answers:
I am Lyosha [343]4 years ago
6 0
Domain is the numbers you can use
you can't use any numbers that make an impossibility like a negative square root or dividing by 0

set the denomenator equal to 0 to find what values of x make it 0
x^3-1=0
add 1 both sides
x^3=1
cube root both sides
x=1
domain is all real numbers except for 1
range is the numbers you get from inputing domaain
there is a vertical assemtote there so all bases are covered
range is how high and low y goes
domain is how far left and right x goes


domain is all real numbers except x=1
range is all real numbers

Volgvan4 years ago
6 0
Find vertical and horizontal asymptotes
vertical: set denominator=0
x^3-1=0
x^3=1
VA=1

horizontal: highest degree of num. < highest degree of den.
HA=0

domain and range
d: (-infinity, 1)U(1, infinity)
r: (-infinity, 0)U(0, infinity)
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Answer:

Carter's bedroom would cost more to carpet than Carly's because the floor area of the former is about five square feet greater than the floor area of Carly's bedroom.

Step-by-step explanation:

The area of either of these floors is found by multiplying length by width:

A = L*W.

Carly's bedroom is 15.3 ft by 8.7 ft; multiplying, we get A = 133.11 ft^2

Carter's is 14.4 ft by 9.6 ft:  A = 138.24 ft^2

Carter's bedroom area (138.24 ft^2) is about 5 ft^2 larger than Carly's and would thus cost more to carpet.

5 0
2 years ago
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How you can use mental math to find the product
Sedbober [7]

Answer:

(10x25) + (5x25)=375

Step-by-step explanation:

Ten times any number is easy because you just add a zero to the end. So mental math would say to break it into 10x25=250, plus 5x25=125, which equals 375

6 0
3 years ago
Moore's law says that the number of transistors in a dense integrated circuit increases by 41\%41%41, percent every year. In 197
stiv31 [10]

Answer:

In 1979 the amount of transistors in a chip was approximately 27865.

Step-by-step explanation:

Since the number of transistors in 1974 was 5000 per chip and it increases at a rate of 41% per year, the number of transistors in a chip per year can be modelled by the following expression:

chips(t) = 5000*(1.41)^(t - 1974)

Therefore in 1979, we have:

chips(1979) = 5000*(1.41)^(1979 - 1974)

chips(1979) = 5000*(1.41)^5

chips(1979) = 27865.4183

In 1979 the amount of transistors in a chip was approximately 27865.

8 0
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