1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tatiyna
3 years ago
15

What is 2x^2+7x-4/x^3 -1

Mathematics
2 answers:
I am Lyosha [343]3 years ago
6 0
Domain is the numbers you can use
you can't use any numbers that make an impossibility like a negative square root or dividing by 0

set the denomenator equal to 0 to find what values of x make it 0
x^3-1=0
add 1 both sides
x^3=1
cube root both sides
x=1
domain is all real numbers except for 1
range is the numbers you get from inputing domaain
there is a vertical assemtote there so all bases are covered
range is how high and low y goes
domain is how far left and right x goes


domain is all real numbers except x=1
range is all real numbers

Volgvan3 years ago
6 0
Find vertical and horizontal asymptotes
vertical: set denominator=0
x^3-1=0
x^3=1
VA=1

horizontal: highest degree of num. < highest degree of den.
HA=0

domain and range
d: (-infinity, 1)U(1, infinity)
r: (-infinity, 0)U(0, infinity)
You might be interested in
How do you solve it?
Elis [28]

At heart we're being asked for a line through two points,


(40^\circ \textrm{ C}, 355 \textrm { m/s}) \quad \textrm{and} \quad (49^\circ \textrm{ C}, 360 \textrm { m/s})


In general the line through (a,b) and (c,d) is


(y-b)(c-a)=(x-a)(d-b)


Check that you understand why both (a,b) and (c,d) are on this line.


Here our indepedent variable, instead of x, is T, temperature. Our dependent variable is v, velocity. Substituting,


(v - 355)(49 - 40) = (T - 40)(360 - 355)


9(v - 355) = 5(T - 40)


v-355 = \frac 5 9 T - \frac{200}{9}


v= \frac 5 9 T - \frac{200}{9} + 355


v= \frac 5 9 T + \frac{2995}{9}


That's our answer; let's check it.


When T=40, v = (5/9)40 + (2995/9) = 355 good


When T=49, v= (5/9)49 + (2995/9) = 360 good




7 0
3 years ago
Fill in the reason that justifies the step to solve for x in the diagram.
aleksandr82 [10.1K]
Answer is 13 42-3=39÷3=13
3 0
3 years ago
Read 2 more answers
What is the gradient of the graph shown?<br> Give your answer in its simplest form.
AlekseyPX

Answer:

m = —1/3

Step-by-step explanation:

There are two clear points shown on the graph

point 1: (0;3)

point 2: (6;1)

m =  \frac{y2 - y1}{x2 - x1}

m =  \frac{1 - 3}{6 - 0}

m =  - \frac{2}{6}

m =  -  \frac{1}{3}

5 0
2 years ago
Read 2 more answers
For the right triangle shown, the lengths of two sides are given. Find the third side. Leave your answer in simplified, radical
Salsk061 [2.6K]
<span>5^2 + 10^2 = 125
c^2 = 125
c = √125 = √(25•5) = = 5√5</span>

7 0
3 years ago
Read 2 more answers
Some students are going on a field trip. The cost of the trip is $100, in addition to $7per student. Write an equation that rela
grigory [225]

Answer: C= 100+7n

Step-by-step explanation:

5 0
2 years ago
Other questions:
  • Write an equation for the line that passes through the given point and is parallel to the graph of the given equation.
    9·1 answer
  • I need this number as an ordinary number
    13·1 answer
  • Help help help plz ❤️Please
    10·1 answer
  • The sum of two numbers is 24.
    6·1 answer
  • A student wants to know how far above the ground the top of a leaning flagpole is. At high​ noon, when the sun is almost directl
    11·1 answer
  • Im wasting my points pls answer
    14·1 answer
  • Anybody know ? Need help
    8·1 answer
  • A Story bought headphones for $50 the mark up the price 65% what is the selling price of the phone.
    9·1 answer
  • Factor 15x^2y^2 - 3x^3y + 75x^4. Show your work. Need to show work and please be 100% honest. Only answer if you know how. Will
    10·2 answers
  • joe received $375 for his graduation He put $205 into his savings account About what Percent of his graduation money did joe put
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!