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Crank
3 years ago
12

YOU WILL GET THE BRAINLIEST IF YOU ANSWER THIS CORRECTLY PLEASE HURRY

Mathematics
1 answer:
Anni [7]3 years ago
4 0

Answer:

yes yes no no

Step-by-step explanation:

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A class of 30 swim team members took a lifesaving test. Eighteen of the members had an average score of 92 points. The remaining
inysia [295]

Answer:

88.8%

Step-by-step explanation:

1.) 30-18= 12 which is the number of member that had an average of 84

2.)Then multiply  12 times 84 = 1008

3.) You multiply 18 by 92 which equals 1656

4.)Add 1008 and 1656 together  and get 2664.

5.)Divide 2664 / 30 and you get the average of 88.8

Hope this helps :)

plz brainly & like

8 0
3 years ago
Read 2 more answers
While Playing Yahtzee and rolling 5 dice, Mei gets the result shown at right (the numbers are 2, 4, 4, 4, and 1). Mei decides to
Elina [12.6K]
A. The probability is 1/36. There are 36 combinations of the first and second dice and only one of them is 2 - 4s.

B. 10/36. Ten of the options contain exactly 1 - 4. 

C. The remaining 25/36 options do not include a 4. 
5 0
3 years ago
In a test of the effectiveness of garlic for lowering​ cholesterol, 8181 subjects were treated with raw garlic. Cholesterol leve
xz_007 [3.2K]

Answer:

With garlic​ treatment, the mean change in LDL cholesterol is not greater than 0.

Step-by-step explanation:

The dependent <em>t</em>-test (also known as the paired <em>t</em>-test or paired samples <em>t</em>-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.

In this case a paired <em>t</em>-test is used to determine the effectiveness of garlic for lowering​ cholesterol.

A random sample of 81 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment.

The hypothesis for the test can be defined as follows:

<em>H₀</em>: With garlic​ treatment, the mean change in LDL cholesterol is not greater than 0, i.e. <em>d</em> ≤ 0.

<em>Hₐ</em>: With garlic​ treatment, the mean change in LDL cholesterol is greater than 0, i.e. <em>d</em> > 0.

The information provided is:

\bar d=0.40\\SD_{d}=16.2\\\alpha =0.01

Compute the test statistic value as follows:

t=\frac{\bar d}{SD_{d}/\sqrt{n}}\\\\=\frac{0.40}{16.2/\sqrt{81}}\\\\=0.22

The test statistic value is 0.22.

Decision rule:

If the <em>p</em>-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

Compute the <em>p</em>-value of the test as follows:

p-value=P(t_{n-1}>0.22)\\=P(t_{80}>0.22)\\=0.4132

*Use a <em>t</em>-table.

The <em>p</em>-value of the test is 0.4132.

<em>p-</em>value= 0.4132 > <em>α</em> = 0.01

The null hypothesis was failed to be rejected.

Thus, it can be concluded that with garlic​ treatment, the mean change in LDL cholesterol is not greater than 0.

3 0
2 years ago
Faction help plz!!!!
Marizza181 [45]
Complete 2/3 x the number of plates
6 0
3 years ago
The museum charges $14 for adult admission and $11 for each child. the museum bill for a school field trip was $896.
lord [1]
14x + 11y = 896

x = number of adults
y= number of kids
if nine adults went then 70 kids went
6 0
3 years ago
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