Answer:
Probability that at least 490 do not result in birth defects = 0.1076
Step-by-step explanation:
Given - The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control and Prevention (CDC). A local hospital randomly selects five births and lets the random variable X count the number not resulting in a defect. Assume the births are independent.
To find - If 500 births were observed rather than only 5, what is the approximate probability that at least 490 do not result in birth defects
Proof -
Given that,
P(birth that result in a birth defect) = 1/33
P(birth that not result in a birth defect) = 1 - 1/33 = 32/33
Now,
Given that, n = 500
X = Number of birth that does not result in birth defects
Now,
P(X ≥ 490) =
= + .......+
= 0.04541 + ......+0.0000002079
= 0.1076
⇒Probability that at least 490 do not result in birth defects = 0.1076
Answer:
x = 5
Step-by-step explanation:
Jeez this diagram is horribly drawn.
16/32 = 26/(32 + 4x)
16(32 + 4x) = 32(26)
32 + 4x = 2(26)
4x = 20
x = 5
Wow, my incorrect answer happened to also be the actual right one, wooh!
Umm u need to give a file link or something
The blank is -6x because -6 + 2 equals -4 min which is on the other side of the equation.