Answer:
a)
The point that is equidistant to all sides of a triangle is called the <u>incenter</u>.
The incenter is located at the intersection of bisectors of the interior angles of a triangle.
b)
The point that is equidistant to all vertices of a triangle is called the <u>circumcenter</u>.
The circumcenter is located at the intersection of perpendicular bisectors of the sides of a triangle.
c)
<em>See the attachment</em>
The blue lines and their intersection shows the incenter.
The red lines and their intersection shows the circumcenter.
As we see the red point- the <u>circumcenter </u>is closer to vertex B.
The surface area formula for any sphere is 4(pi)(radius)^2
The radius is half of the diameter.
18.6 / 2 = 9.3
So, plug into the formula and solve.
4(3.14)(9.3)^2 = 1086.3 mm^2
The correlation coefficient is -0.87; strong correlation
<h3>How to determine the correlation coefficient?</h3>
The given parameters are:
x = Time spent working out
y = lbs Overweight
Next, we enter the table of values in a graphing tool.
From the graphing tool, we have the following summary:
<u>X Values</u>
- ∑ = 27.1
- Mean = 2.71
- ∑(X - Mx)2 = SSx = 22.569
<u>Y Values</u>
- ∑ = 89
- Mean = 8.9
- ∑(Y - My)2 = SSy = 778.9
<u>X and Y Combined</u>
- N = 10
- ∑(X - Mx)(Y - My) = -114.19
<u>R Calculation</u>
r = ∑((X - My)(Y - Mx)) / √((SSx)(SSy))
r = -114.19 / √((22.569)(778.9))
r = -0.8613
Approximate
r = -0.87
This means that the correlation coefficient is -0.87
Also, the correlation coefficient is a strong correlation, because it is closer to -1 than it is to 0
Read more about correlation coefficient at:
brainly.com/question/27226153
#SPJ1
(-2,8) This is a answer:)
(a) The "average value" of a function over an interval [a,b] is defined to be
(1/(b-a)) times the integral of f from the limits x= a to x = b.
Now S = 200(5 - 9/(2+t))
The average value of S during the first year (from t = 0 months to t = 12 months) is then:
(1/12) times the integral of 200(5 - 9/(2+t)) from t = 0 to t = 12
or 200/12 times the integral of (5 - 9/(2+t)) from t= 0 to t = 12
This equals 200/12 * (5t -9ln(2+t))
Evaluating this with the limits t= 0 to t = 12 gives:
708.113 units., which is the average value of S(t) during the first year.
(b). We need to find S'(t), and then equate this with the average value.
Now S'(t) = 1800/(t+2)^2
So you're left with solving 1800/(t+2)^2 = 708.113
<span>I'll leave that to you</span>
