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torisob [31]
3 years ago
5

The sun converts ——— energy into ——— energy.

Physics
1 answer:
velikii [3]3 years ago
7 0

The sun converts fusion energy into radiant (electromagnetic) energy.

<u>Explanation: </u>

The energy which we get from the sun is called Solar Energy. The Solar Energy is nothing but, a form of energy, which is left out from an exothermic reaction. The radiant energy is the solar energy. The sun gets its energy through nuclear fusion.

High temperature causes the sun’s nuclei to separate from electrons. And with these electrons, the hydrogen ions combine to form Helium, which is the source of energy for the sun. As the nuclear fusion continues, the energy is derived and we get solar energy.

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Distance = 6 km south<br><br> 60 minutes<br><br> What was the average velocity
blsea [12.9K]

v = x/t

v = average velocity, x = displacement, t = elapsed time

Given values:

x = 6km south, t = 60min

Plug in and solve for v:

v = 6/60

v = 0.1km/min south

3 0
4 years ago
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When the same masses are heated by the same amount, which of the following substances will heat up the slowest?
DochEvi [55]
When the same masses are heated by the same amount copper will heat up the fastest. Copper is a good conductor of heat that is why it easily heats up. Gold is not a good conductor of heat because of its stable properties.
8 0
3 years ago
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In the great shopping cart race, two students push on shopping carts. A having twice the mass of B, with the same force applied
Lesechka [4]

K = 1/2 m x v^2

m = mass on the cart

V = velocity imparted to the cart

KA = 1/2 mA x vA^2.......................(1)

KB = 1/2 mB x vB^2........................(2)

Diving equation 1 by equation 2, we get -

KA/KB = mA/mB

= 2

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6 0
4 years ago
A furlong is an old british unit of length equal to 0.125 mi, derived from the length of a furrow in an acre of ploughed land. a
castortr0y [4]

The speed of light is: c = 3x10^8 m/s <span>

or 

c = 186,000,000 miles/sec = 1.86x10^8 mi/s 

1 furlong = 0.125 mile 

1 fortnight = 2 weeks(7d/wk)(24h/d)(3600s/h) 
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Therefore, 

c =1.86x10^8 mi/s(1furl/0.125mi)(1.2096x10^6s/fort) 

<span>c = 18x10^14 furlong/fortnight = 18x10^8 Mfurlong/fortnight</span></span>

4 0
4 years ago
A 2.98-kg object oscillates on a spring with an amplitude of 8.05 cm. Its maximum acceleration is 3.55 m/s2. Calculate the total
Aloiza [94]

Answer:

a = ω^2 A      formula for max acceleration (ignoring sign)

V = ω A         formula for max velocity

V^2 = ω^2 A^2 = a A   from first equation

E = 1/2 M V^2 = 1/2 * 2.98 * 3.55 * .0805 = .426 J

(kg * m/sec^2 * m = kg m^2 / sec^2 = Joule

6 0
2 years ago
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