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Keith_Richards [23]
3 years ago
6

If the velocity of gas molecules is doubled, then it’s kinetic energy will?( hint formula for kinetic energy is KE=.5 x mv2)

Physics
2 answers:
eduard3 years ago
7 0

Answer:

D quadruple

Explanation:

E = \frac{1}{2}mv^2\\E'=\frac{1}{2}m(2v)^2=\frac{1}{2}m4 v^2 = 4(\frac{1}{2}mv^2)=4E

AysviL [449]3 years ago
3 0

Answer:

(D) quadruple

Explanation:

KE_{1} = \frac{1}{2}m v^{2} -----equation 1

where;

KE₁ is the initial kinetic energy

m is the gas molecule mass

v is the velocity of gas molecules

⇒ When the velocity of gas molecules is doubled (2v)

KE_{2} = \frac{1}{2}m (2v)^{2}

KE_{2} = \frac{1}{2}m*4v^{2}

KE_{2} = 4(\frac{1}{2}mv^2) -------equation 2

Recall; From equation 1;

KE_{1} = \frac{1}{2}m v^{2}

Substitute in KE₁ in equation 2

KE₂ = 4(KE₁)

Therefore, the kinetic energy will quadruple

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