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4 years ago

The image represents what ?

Physics

1 answer:

nikitadnepr [17]4 years ago

6 0

Answer:

what image. what i see is nothing. so i say it represents a failing grade. just kidding but i do not know what the image is so i can not answer the question .

Explanation:

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A 4.50-kg wheel that is 34.5 cm in diametet rotates through an angle of 13.8 rad as it slows down uniformly from 22.0 rad/s to 1

lisabon 2012 [21]

Answer:

$\alpha =10.93radian/sec^2$

Explanation:

We have given given the final angular velocity $\omega _{final}=13.5rad/sec$

And $\omega _{initial}=22rad/sec$

Displacement $\Theta =13.8radian$

We have to find the angular acceleration $\alpha$

According to law of motion $\omega _{final}^2=\omega _{initial}^2+2\alpha \Theta$

So $13.5^2=22^2+2\times \alpha \times 13.8$

$\alpha =-10.93radian/sec^2$

In question we have tell about magnitude only so $\alpha =10.93radian/sec^2$

4 0

3 years ago

A 67 Vrms source is placed across a load that consists of a 12 ohm resistor in series with an capacitor whose reactance is 5 ohm

SVETLANKA909090 [29]

a) The average true power is 318.3 W

b) The reactive power is 132.6 W

c) The apparent power is 344.8 W

d) The power factor is 0.92

Explanation:

For a circuit made of a resistor and a capacitor, the average (true) power is given by the resistive part of the circuit only.

Therefore, the average true power is given by:

$P=I^2R$

where

I is the current

R is the resistance

In this problem, we have

V = 67 V (rms voltage)

$R=12 \Omega$ is the resistance of the load

$X=5\Omega$ is the reactance of the circuit

First we have to find the impedance of the circuit:

$Z=\sqrt{R^2+X^2}=\sqrt{12^2+5^2}=13 \Omega$

Then we can find the current in the circuit by using Ohm's law:

$I=\frac{V}{Z}=\frac{67}{13}=5.15 A$

Therefore, the average true power is

$P=I^2R=(5.15)^2(12)=318.3 W$

The reactive power of a circuit consisting of a resistor and a capacitor is the power given by the capacitive part of the circuit.

Therefore, it is given by

$Q=I^2X$

where

I is the current

X is the reactance of the circuit

In this circuit, we have

$I=5.15 A$ (current)

$X=5 \Omega$ (reactance)

Therefore, the reactive power is

$Q=(5.15)^2(5)=132.6W$

In a circuit with a resistor and a capacitor, the apparent power is given by both the resistive and capacitive part of the circuit.

Therefore, it is given by

$S=I^2Z$

where

I is the current

Z is the impedance of the circuit

Here we have

I = 5.15 A (current)

$Z=13 \Omega$ (impedance)

Therefore, the apparent power is

$S=I^2 Z=(5.15)^2(13)=344.8 W$

For a circuit with a resistor and a capacitor, the power factor is the ratio between the true power and the apparent power. Mathematically:

$PF=\frac{P}{S}$

where

P is the true power

S is the apparent power

For this circuit, we have

P = 318.3 W (true power)

S = 344.8 W (apparent power)

So, the power factor is

$PF=\frac{318.3}{344.8}=0.92$

Learn more about power and circuits:

brainly.com/question/4438943

brainly.com/question/10597501

brainly.com/question/12246020

#LearnwithBrainly

3 0

3 years ago

Two forces, F⃗ 1F→1F_1_vec and F⃗ 2F→2F_2_vec, act at a point,F⃗ 1F→1F_1_vec has a magnitude of 8.80 NN and is directed at an an

castortr0y [4]

Answer:

Fx = -9.15 N
Fy = 1.72 N
F∠γ ≈ 9.31∠-10.6°

Explanation:

You apparently want the sum of forces ...

F = 8.80∠-56° +7.00∠52.8°

Your angle reference is a bit unconventional, so we'll compute the components of the forces as ...

f∠α = (-f·cos(α), -f·sin(α))

This way, the 2nd quadrant angle that has a negative angle measure will have a positive y component.

= -8.80(cos(-56°), sin(-56°)) -7.00(cos(52.8°), sin(52.8°))

≈ (-4.92090, 7.29553) +(-4.23219, -5.57571)

≈ (-9.15309, 1.71982)

The resultant component forces are ...

Fx = -9.15 N
Fy = 1.72 N

Then the magnitude and direction of the resultant are

F∠γ = (√(9.15309² +1.71982²))∠arctan(-1.71982/9.15309)

F∠γ ≈ 9.31∠-10.6°

4 0

3 years ago

Acar goes from 20m/s to 30m/s in 10 seconds what is its acceleration

prohojiy [21]

Acceleration = change in velocity/change in time

= (30 - 20) / 10 - 0

= 10 / 10

Acceleration = 1 m/s²

8 0

3 years ago

100 POINTS!!!

nignag [31]

Answer:

very low air pressure and that's not 100 points

6 0

3 years ago