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3 years ago

What is the weight of a 5.5kg bowling ball

Physics

1 answer:

Marrrta [24]3 years ago

4 0

Answer:

2.205 pounds

Explanation:

5.5 kg is 2.205 lbs. hope this helps!

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A book is sitting on a desk. What best describes the normal force acting on the book?

Marat540 [252]

Explanation:

in my opinion I'd say it's gravity because it's making the book stay in it's one and only position pulling the book at the center of the desk

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3 years ago

Read 2 more answers

A tow rope pulls a 1450 kg truck, giving it an acceleration 1.25 m/s^2. What force does the rope exert?

bagirrra123 [75]

force=mass × acceleration

mass=force ÷ acceleration

acceleration=force ÷ mass

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3 years ago

The maximum number of electrons in the second energy level of an atom is ____.

ehidna [41]

Your answer will be 8.

6 0

3 years ago

A horizontal board of negligible thickness and area 2.0 m2 hangs from a spring scale that reads 80 N when a 4.0 m/s wind moves b

ki77a [65]

Answer:

Scale reading for no wind $W'=60N$

Explanation:

From the question we are told that

Area $A= 2.0 m^2$

Weight of board $W=80$

Velocity $V=4.0m/s$

Density of air $\delta= 1.25 kg/m3 .$

Generally the equation for pressure difference by Bernoulli equation is mathematically given by

$dP=\frac{1}{2}pv^2$

$dP=10Pa$

Generally force acting on the board by air is mathematically given by

$F=\triangle PA$

$F=(10)2=>20N$

Therefore

Scale reading for no wind W'

$W'=W-F\\W'=80-20$

$W'=60N$

Scale reading for no wind W'=60N

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3 years ago

Vector A has magnitude 8.00 mm and is in the xy-plane at an angle of 127∘ counterclockwise from the +x–axis (37∘ past the +y-axi

Ilia_Sergeevich [38]

Answer:

-75.35°

Explanation:

Let C be the sum of the two vectors A and B. Hence, we can write the following

$A_{x} +B_{x} =C_{x} ......(1)\\A_{y} +B_{y} =C_{y} ......(2)$

but since the vector C is in the -y direction, $C_{x}$ = 0 and $C_{y}$ = —12 m.

Thus

$B_{x} =-A_{x} =-[-Acos(180-127)]=(8)*cos(53)\\B_{x} =4.81m$

similarly, we can determine $B_{y}$ by rearranging equation (1)

$B_{y} =C_{y} -A_{y} =-12m-[(8)*sin(53)\\B_{y} =-18.4m$

so the magnitude of B is

$B=\sqrt{B_{x}^2+B_{y}^2 } \\B=19m$

Finally, the direction of B can be calculated as follows

Ф= $tan^{-1} (\frac{B_{y} }{B_{x} } )\\=-75.35$

hence the vector B makes an angle of 75.35 clockwise with + x axis

8 0

4 years ago