Answer:
1) pH=3
2) its colour is blue in basic solution
3) KOH(aq) +HCl(aq) ------> KCl(aq) + H2O(l)
4) 0.02 M
5) increase in solution concentration (number of ions present in solution) increases its electrical conductivity
Explanation:
1) A solution ten times less acidic than the HCl(aq) will have a concentration of 0.001M
Hence from pH= -log[H^+].
pH= - log(0.001)
pH= 3
2) its colour is blue in basic solution
3) KOH(aq) +HCl(aq) ------> KCl(aq) + H2O(l)
4)
from
CA= concentration of acid= 0.010M
CB= concentration of base= ????
VA= volume of acid= 15.0mL
VB= volume of base= 7.5mL
NA= number of moles of acid= 1
NB= number of moles of base= 1
CAVA/CBVB=NA/NB
CAVANB=CBVBNA
CB= CAVANB/VB NA
CB= 0.01 ×15.0 × 1/ 7.5 ×1
CB= 0.02 M
5) The more concentrated the solution is, the more the number ions present and the better the conductivity of the solution. Hence the more concentrated 1.0M HCl(aq) contains more ions and is a better conductor of electricity than 0.01M HCl(aq)