Answer:
The Ka is 3.74 *10^-4
Explanation:
Step 1: Data given
Mass of aspirin = 2.00 grams
Volume of water = 0.600 L
pH of solution = 2.61
Molar mass of acetylsalicylic acid = 180 g/mol
Step 2: The balanced equation
C9H8O4 + H2O ⇆ H3O+ + C9H7O4-
Step 3: Calculate moles acetylsalicylic acid
Moles acetylsalicylic acid = mass / molar mass
Moles acetylsalicylic acid = 2.00 grams / 180 g/mol
Moles acetylsalicylic acid = 0.0111 moles
Step 4: The initial concentration
[C9H8O4] = 0.0111 moles / 0.600 L = 0.0185 M
[H3O+] = 0M
[C9H8O4-] = 0M
Step 5: The concentration at the equilibrium
[C9H8O4] =0.0185 - X M
[H3O+] = XM
[C9H8O4-] = XM
Step 6: Calculate Ka
Ka = [H3O+][C9H7O4-] / [C9H8O4]
Ka = x² / (0.0185 - x)
pH = 2.61; [H3O+] = 10^-pH = 10^-2.61 = 0.00245 = x
Ka = (0.00245)² / (0.0185 - 0.00245) = 3.74 * 10^-4
The Ka is 3.74 *10^-4
The normal range of creatinine in human blood is between 0.50 mg/dL and 1.1 mg/dL. The patient's blood has a concentration of 0.0082 g/L. Let's convert that value into mg/dL.
We kwnot that there are 1000 mg in 1 g. And there are 10 dL in 1 L. We have to use those conversions.
1000 mg = 1 g 10 dL = 1 L
0.0082 g/L = 0.0082 g/L * 1000 mg/g = 8.2 mg/L * 1 L/ (10 dL) = 0.82 mg/dL
0.0082 g/L = 0.82 mg/dL
0.50 mg/dL < 0.82 mg/dL < 1.1 mg/dL
Answer: The concentration of creatinine = 0.82 mg/dL. It is in the normal range.
4Fe + 3O2 -> 2 (Fe2O3)
Both sides have 4Fe and 6O.
Must be C because the liquid fuel is Codium nitrate to be used in rocket engines