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Hitman42 [59]
3 years ago
10

A region of metamorphic rock lies far beneath Earth’s surface. In time, which two ways can the rock make its way upward to Earth

’s surface, where people are able to see it? MULTIPLE CHOICE a.-It can be transported by water and deposited on Earth’s surface. b.-It can uplift slowly due to the pressure of Earth’s plates. c.-It can become intrusive igneous rock through compaction and cementation. d.-It can be transported by wind and deposited on Earth’s surface. e.-It can melt into magma and recrystallize as extrusive igneous rock.
Chemistry
2 answers:
NeX [460]3 years ago
8 0

It can uplift slowly due to the pressure of Earth’s plates.

It can melt into magma and recrystallize as extrusive igneous rock.

Evgen [1.6K]3 years ago
3 0

Answer:

Option (B) and (E)

Explanation:

Metamorphic rocks are the rocks that are formed due to the increasing pressure and temperature condition. These are secondary rocks and are directly derived from either igneous, sedimentary or other types of metamorphic rocks. For example, Schist, Gneiss, Marble, and Quartzite.

These rocks are located both at and beneath the earth's surface. These rocks can be exposed in an outcrop if the rocks are melted due to the extremely high temperature, as a result of which the melt will turn into magma and this magma further undergoes crystallization due to the lowering of temperature and forms an extrusive type of igneous rocks.

In addition to this, these rocks can also come to the surface if the lithospheric plates containing these metamorphic rocks are forced to rise up in a convergent or a divergent type of plate tectonic boundary.

Thus, the correct answer is option (B) and (E).

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An ideal solution consisting of 79 wt% benzene (C6H6) and 21 wt% toluene (C7H8) was heated in a closed vessel to 50 ºC. What is
Thepotemich [5.8K]

In this case, according to the Raoult's law, we can find the mole fraction of 79 wt% benzene and 21 wt% toluene at 50 °C in the vapor phase as follows:

y_iP=x_iP_i

However, we first have to calculate the mole fractions in the solution as follows (b stands for benzene and t for toluene):

\\x_b=0.79\frac{g\ benzene}{g\ solution} *\frac{(78.11*x_b+92.14*x_t)}{1mol\ solution} *\frac{1mol\ toluene}{78.11g\ toluene} \\\\x_b=0.79\frac{g\ benzene}{g\ solution} *\frac{78.11*x_b+92.14*(1-x_b)}{1mol\ solution} *\frac{1mol\ toluene}{78.11g\ toluene}\\\\x_b=0.79*(x_b+1.18*(1-x_b))\\\\x_b=0.79x_b+0.932-0.932x_b\\\\x_b=\frac{0.932}{1+0.932-0.79} =0.816\\\\x_t=1-x_b=1-0.816=0.184

Next, we calculate the total pressure as follows, according to the Dalton's law:

P=x_bP_b+x_tP_t=0.816*271mmHg+0.184*91.5mmHg=237.972mmHg

Finally, the mole fractions of the vapor phase turn out:

y_b=\frac{0.816*271mmHg}{237.972mmHg}=0.929\\\\y_t=1- 0.929=0.071

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5 0
2 years ago
Which process produces co2?
SashulF [63]

burning of fossil fuels is the answer

7 0
2 years ago
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In an attempt to maximize the yield of methanol (amount of methanol produced), a chemist would try to shift the equilibrium as f
MakcuM [25]

Answer:

removing the methanol as it is formed

Explanation:

One of the ways to drive the equilibrium position towards the right is to remove one of the products formed.

According to Me Chatelier's principle, the imposition of a constraint on a system in a equilibrium causes the equilibrium position to shift towards a new position that annuls the constraint. Hence, removing the methanol causes the equilibrium position to shift to the far right in order to reestablish equilibrium according to Le Chatelier's principle.

3 0
3 years ago
If you run this reaction with 15 g of CuCl2 and 20 g NaNO3, what is the theoretical yield of NaCl?
Margaret [11]

The theoretical yield of a substance is the amount of the mass that is calculated from stoichiometry. The mass of sodium chloride produced is 13.03 gms.

<h3>What is mass?</h3>

Mass of the substance is a multiplication of the molar mass and moles.

The balanced reaction is given as:

CuCl₂ + 2NaNO₃ ⇒ 2NaCl + Cu(NO₃)₂

Moles of copper chloride are calculated as: 15 ÷ 134.45 = 0.115 moles

Moles of sodium nitrate are calculated as: 20 ÷ 84.99 = 0.2353 moles

From the reaction, 1 mole of copper chloride gives 2 moles of sodium chloride so, 0.115 moles of copper chloride will produce 0.223 moles.

Similarly, 2 moles of sodium nitrate produce 2 moles of sodium chloride so, 0.2353 moles produce 0.4706 moles.

From this, it can be concluded that copper chloride is a limiting reagent and will be used to calculate the mass of NaCl.

Mass of NaCl is calculated as: Mass = 0.223 moles × 58.44 = 13.03 gms.

Therefore, 13.03 gms is the theoretical yield of sodium chloride.

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7 0
2 years ago
Carbon tetrachloride can be produced by the following reaction: Suppose 1.20 mol of and 3.60 mol of were placed in a 1.00-L flas
hjlf

The given question is incomplete. The complete question is :

Carbon tetrachloride can be produced by the following reaction:

CS_2(g)+3Cl_2(g)\rightleftharpoons S_2Cl_2(g)+CCl_4(g)

Suppose 1.20 mol CS_2(g) of and 3.60 mol of Cl_2(g)  were placed in a 1.00-L flask at an unknown temperature. After equilibrium has been achieved, the mixture contains 0.72 mol  of CCl_4. Calculate equilibrium constant at the unknown temperature.

Answer: The equilibrium constant at unknown temperature is 0.36

Explanation:

Moles of  CS_2 = 1.20 mole

Moles of  Cl_2 = 3.60 mole

Volume of solution = 1.00  L

Initial concentration of CS_2 = \frac{moles}{volume}=\frac{1.20mol}{1L}=1.20M

Initial concentration of Cl_2 = \frac{moles}{volume}=\frac{3.60mol}{1L}=3.60M

The given balanced equilibrium reaction is,

                 CS_2(g)+3Cl_2(g)\rightleftharpoons S_2Cl_2(g)+CCl_4(g)

Initial conc.         1.20 M        3.60 M                  0                  0

At eqm. conc.     (1.20-x) M   (3.60-3x) M   (x) M        (x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[S_2Cl_2]\times [CCl_4]}{[Cl_2]^3[CS_2]}

Now put all the given values in this expression, we get :

K_c=\frac{(x)\times (x)}{(3.60-3x)^3\times (1.20-x)}

Given :Equilibrium concentration of CCl_4 , x = \frac{moles}{volume}=\frac{0.72mol}{1L}=0.72M

K_c=\frac{(0.72)\times (0.72)}{(3.60-3\times 0.72)^3\times (1.20-0.72)}

K_c=0.36

Thus equilibrium constant at unknown temperature is 0.36

4 0
3 years ago
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