1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rina8888 [55]
3 years ago
14

Help me please and thank you!! :)(answers non-related will be reported sorry!!)

Mathematics
2 answers:
lord [1]3 years ago
5 0
Answer- 28m+24f. Simplify the expression
Igoryamba3 years ago
3 0

Answer:

28m+24f

Step-by-step explanation:

just simplify as u normally would :)

You might be interested in
Help please..............
Aleonysh [2.5K]

Answer:

Basically ur wrong

Step-by-step explanation:

6 0
3 years ago
How many terms are there in the sequence 1, 8, 28, 56, ..., 1 ?
BabaBlast [244]

Answer:

9 terms

Step-by-step explanation:

Given:  

1, 8, 28, 56, ..., 1

Required

Determine the number of sequence

To determine the number of sequence, we need to understand how the sequence are generated

The sequence are generated using

\left[\begin{array}{c}n&&r\end{array}\right] = \frac{n!}{(n-r)!r!}

Where n = 8 and r = 0,1....8

When r = 0

\left[\begin{array}{c}8&&0\end{array}\right] = \frac{8!}{(8-0)!0!} = \frac{8!}{8!0!} = 1

When r = 1

\left[\begin{array}{c}8&&1\end{array}\right] = \frac{8!}{(8-1)!1!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8

When r = 2

\left[\begin{array}{c}8&&2\end{array}\right] = \frac{8!}{(8-2)!2!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} =2 8

When r = 3

\left[\begin{array}{c}8&&3\end{array}\right] = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56

When r = 4

\left[\begin{array}{c}8&&4\end{array}\right] = \frac{8!}{(8-4)!4!} = \frac{8!}{4!3!} = \frac{8 * 7 * 6 * 5 * 4!}{4! *4*3* 2 *1} = \frac{8 * 7 * 6*5}{4*3 *2 *1} = 70

When r = 5

\left[\begin{array}{c}8&&5\end{array}\right] = \frac{8!}{(8-5)!5!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56

When r = 6

\left[\begin{array}{c}8&&6\end{array}\right] = \frac{8!}{(8-6)!6!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} = 28

When r = 7

\left[\begin{array}{c}8&&7\end{array}\right] = \frac{8!}{(8-7)!7!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8

When r = 8

\left[\begin{array}{c}8&&8\end{array}\right] = \frac{8!}{(8-8)!8!} = \frac{8!}{8!0!} = 1

The full sequence is: 1,8,28,56,70,56,28,8,1

And the number of terms is 9

3 0
3 years ago
Pearp deposited 60 into a savings account for which interest is compounded monthly accodring to the rule of 72 what interest rat
denpristay [2]
According to the rule of 72, that rate will be 72/33 ≈ 2.18 percent.
7 0
3 years ago
Please Help me !!!!!!!!!!! X=
Alex787 [66]
Try x = 65
Look at my image
8 0
3 years ago
Given that € 1 = £0.72<br> a) How much is € 410 in £?<br> b) What is the £ to € exchange rate?
Alekssandra [29.7K]

Answer:

a) 295.2

Step-by-step explanation:

a) cross multiplication method

€1=£0.72

€410=x

x=€410×£0.72

8 0
3 years ago
Other questions:
  • A florist is making flower arrangements with 32 roses and 40 tulips. Each arrangement must be identical. What is the greatest nu
    5·1 answer
  • Which is true about this division problem? Select all
    15·2 answers
  • What is the solution of 4x - 6 = -6x - 4?
    13·1 answer
  • Write an equation of the circle with center (4,5) and radius 9.
    10·2 answers
  • How many times does 2 go into 64
    9·2 answers
  • Orginal amount: 12; New amount: 18
    10·1 answer
  • Jen has three bracelets each bracelet has seven diamonds how many diamonds does Jen have in all 
    13·2 answers
  • HELP DUE IN 15 MINS!<br><br> x =??
    9·2 answers
  • square field has a side 150 m long .There is a road 5 m wide all around the park outside it .Find the cost of constructing the r
    9·1 answer
  • Find the value of y.​
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!