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Aleksandr [31]
3 years ago
8

To obtain the desired speedup, make sure your new function recursively calls itself no more than once in the body of the method.

Computers and Technology
1 answer:
sertanlavr [38]3 years ago
8 0

Answer:

the answer is going to be a. true

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(Business: check ISBN-10) An ISBN-10 (International Standard Book Number) consists of 10 digits: d1d2d3d4d5d6d7d8d9d10. The last
Aneli [31]

Answer:

 The solution code is written in Python 3

  1. digits = input("Enter 9 digits: ")
  2. multiplier = 1
  3. total = 0
  4. for x in digits:
  5.    total += int(x) * multiplier  
  6.    multiplier += 1
  7. checksum = total % 11  
  8. if(checksum == 10):
  9.    print(digits + "X")
  10. else:
  11.    print(digits + str(checksum))

Explanation:

Firstly, use input function to get user input for 9 digits (Line 1)

Next we can use a for-loop to estimate the summation (d1 * 1 + d2 * 2 + d3 * 3 + d4 * 4 + d5 * 5+ d6 * 6 + d7 * 7 + d8 * 8 + d9 * 9) ( Line 6-8)

Then only apply % operator to get the remainder of total and get the checksum (Line 10)

Next create if and else statement to print the digits string joined with X if checksum is 10 else join digits string with checksum value (Line 12 -15)

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3 years ago
Create a Produceclass that hasan instance variable of type Stringfor the name, appropriate constructors, appropriate accessor an
Nezavi [6.7K]

Answer:

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Explanation:

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Will somebody please explain to me HTML?
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Scorpion4ik [409]
14) Answer: Feathered images

15) Answer: Scale

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3 years ago
Write a piece of code that constructs a jagged two-dimensional array of integers named jagged with five rows and an increasing n
Ksivusya [100]

Answer:

Explanation:

The following code is written in Java and it uses nested for loops to create the array elements and then the same for loops in order to print out the elements in a pyramid-like format as shown in the question. The output of the code can be seen in the attached image below.

class Brainly {

   public static void main(String[] args) {

       int jagged[][] = new int[5][];

       int element = 1;

       for(int i=0; i<5; i++){

           jagged[i] = new int[i+1]; // creating number of columns based on current value

           for(int x = 0; x < jagged[i].length; x++) {

               jagged[i][x] = element;

               element += 1;

           }

       }

       System.out.println("Jagged Array elements are: ");

       for ( int[] x : jagged) {

           for (int y : x) {

               System.out.print(y + " ");

           }

           System.out.println(' ');

       }

       }

   }

4 0
3 years ago
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