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ddd [48]
4 years ago
12

A sports car starts from rest at an intersection and accelerates toward the east on a straight road at 9.0 m/s2. Just as the spo

rts car starts to move, a bus traveling east at a constant 16 m/s on the same straight road passes the sports car. When the sports car catches up with and passes the bus, how much time has elapsed
Physics
1 answer:
Mamont248 [21]4 years ago
5 0

Answer:

3.6s

Explanation:

Have In mind that the sports car will catch up with bus when their positions are equal

So

S = ut + 1/2at²

where u is initial velocity

For sports car we have

x = 0 + 1/2 x 9 x t²

For Bus

S= 16ts + 0

Equating the two

1/2 x 9 x t² = 16t

4.5 x t = 16

t = 3.6s

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A vector in the xy plane has components -14.0 units in the x-direction and 30.0 units in the y-direction. What is the magnitude
OverLord2011 [107]

\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}

We would calculate the magnitude by applying pythagorean theorem:

\longrightarrow \sf{Magnitude= \sqrt{(-14)^2 } + 30^2}

\longrightarrow \sf{Magnitude = 33.12}

\longrightarrow \sf{The \:  vector \: is \: (- 14, 30)}

The angle between two vectors is given by the formula:

\sf{\longrightarrow \small  \cos \emptyset =  \dfrac{(a1b1 + a2b2)}{ \sqrt{(a1)^2 + (a2)^2√(b1)^2 + (b2)^2} } }

In two dimensional, the x axis of vector form is:

\small\sf{\longrightarrow (b1, b2) = (1, 0) }

\sf{\longrightarrow \small \cos \:  \emptyset =  \dfrac{(14 * 1 + 30 x 0)}{( \sqrt{(-14)^2 + (30)^2)(√(1)^2 + (0)^2)} } }

\small\longrightarrow \sf{ \dfrac{14}{33.12} }

\small\longrightarrow \sf{\emptyset  \:  = arcCos (\dfrac{ - 14}{33.12} )}

\small\longrightarrow \sf{\emptyset= 115^\circ}

\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}

\small\bm{The \: angle  \: between  \: the  \: vector \: }

\small\bm{and \: \: the \: \: positive \: \: x \: \: axis \: \: is \: \: \: 115^\circ .}

6 0
2 years ago
A baseball is hit high into the upper bleachers of left field. Over its entire flight the work done by gravity and the work done
otez555 [7]

Answer:

B. positive; negative.

Explanation:

From the viewpoint of Principle of Energy Conservation and Work-Energy Theorem, we notice that gravity represents a conservative force, associated with gravitational potential energy, whereas air resistance is a non-conservative force, associated with dissipated work. Therefore, the work done by gravity is positive and work done by air resistance is negative. Therefore, the correct answer is B.

5 0
3 years ago
The earth's radius is 6.37×106m; it rotates once every 24 hours.What is the speed of a point on the earth's surface located at 3
bagirrra123 [75]

Answer:

v = 120 m/s

Explanation:

We are given;

earth's radius; r = 6.37 × 10^(6) m

Angular speed; ω = 2π/(24 × 3600) = 7.27 × 10^(-5) rad/s

Now, we want to find the speed of a point on the earth's surface located at 3/4 of the length of the arc between the equator and the pole, measured from equator.

The angle will be;

θ = ¾ × 90

θ = 67.5

¾ is multiplied by 90° because the angular distance from the pole is 90 degrees.

The speed of a point on the earth's surface located at 3/4 of the length of the arc between the equator and the pole, measured from equator will be:

v = r(cos θ) × ω

v = 6.37 × 10^(6) × cos 67.5 × 7.27 × 10^(-5)

v = 117.22 m/s

Approximation to 2 sig. figures gives;

v = 120 m/s

8 0
4 years ago
What does the prefix for kilo- mean
artcher [175]
The word/prefix "kilo" means one thousad

Good luck on your assignment and enjoy your day!

~MeIsKaitlyn :) 
3 0
4 years ago
lace each example of a collision in correct category. bumper cars colliding man jumping in a cab mud sticking to car hat being s
Marrrta [24]

Answer:

bumper cars colliding- inelastic

man jumping in a cab- perfectly inelastic

mud sticking to car - perfectly inelastic

hat being sat on door being slammed- inelastic

ball bouncing- elastic

Explanation:

In a perfectly inelastic collision, the objects stick together after collision and move with a common velocity. Maximum kinetic energy is lost during such collision.

For an inelastic collision, kinetic energy is partly lost and the colliding objects move apart at different velocities. This is often encountered in real life situations.

For an elastic collision, both momentum and kinetic energy are conserved. The object rebounds with the same relative velocity with which it approached.

3 0
4 years ago
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