
We would calculate the magnitude by applying pythagorean theorem:



The angle between two vectors is given by the formula:

In two dimensional, the x axis of vector form is:








Answer:
B. positive; negative.
Explanation:
From the viewpoint of Principle of Energy Conservation and Work-Energy Theorem, we notice that gravity represents a conservative force, associated with gravitational potential energy, whereas air resistance is a non-conservative force, associated with dissipated work. Therefore, the work done by gravity is positive and work done by air resistance is negative. Therefore, the correct answer is B.
Answer:
v = 120 m/s
Explanation:
We are given;
earth's radius; r = 6.37 × 10^(6) m
Angular speed; ω = 2π/(24 × 3600) = 7.27 × 10^(-5) rad/s
Now, we want to find the speed of a point on the earth's surface located at 3/4 of the length of the arc between the equator and the pole, measured from equator.
The angle will be;
θ = ¾ × 90
θ = 67.5
¾ is multiplied by 90° because the angular distance from the pole is 90 degrees.
The speed of a point on the earth's surface located at 3/4 of the length of the arc between the equator and the pole, measured from equator will be:
v = r(cos θ) × ω
v = 6.37 × 10^(6) × cos 67.5 × 7.27 × 10^(-5)
v = 117.22 m/s
Approximation to 2 sig. figures gives;
v = 120 m/s
Answer:
bumper cars colliding- inelastic
man jumping in a cab- perfectly inelastic
mud sticking to car - perfectly inelastic
hat being sat on door being slammed- inelastic
ball bouncing- elastic
Explanation:
In a perfectly inelastic collision, the objects stick together after collision and move with a common velocity. Maximum kinetic energy is lost during such collision.
For an inelastic collision, kinetic energy is partly lost and the colliding objects move apart at different velocities. This is often encountered in real life situations.
For an elastic collision, both momentum and kinetic energy are conserved. The object rebounds with the same relative velocity with which it approached.