What energy is present when a magnet is moving?

Which of the following statements about geothermal energy is not true?

Greeley [361]

Answer:

The answer is C

Explanation:

8 0

4 years ago

A summary of a source is usually

Mekhanik [1.2K]

Answer:

A shorter than the original source and in the researcher's words

Explanation:

The summary is an abridged version of the original source and in the researcher's own very words.

Summaries gives an over-arching perspective and excludes implicit details from a given text.

A summary should not be detailed and must avoid overt illustrations. They must capture the true essence of piece leaving out flowery details.

A summary should be lesser in length than the original piece. Any third party reader should immediately be able to grab the details of the original piece from the summary.

5 0

4 years ago

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A ball is thrown upward with a speed of 28.2 m/s.A. What is its maximum height?B. How long is the ball in the air?C. When does t

Ede4ka [16]

Answer:

(A) The maximum height of the ball is 40.57 m

(B) Time spent by the ball on air is 5.76 s

(C) at 33.23 m the speed will be 12 m/s

Explanation:

Given;

initial velocity of the ball, u = 28.2 m/s

(A) The maximum height

At maximum height, the final velocity, v = 0

v² = u² -2gh

u² = 2gh

$h = \frac{u^2}{2g}\\\\h = \frac{(28.2)^2}{2*9.8}\\\\h = 40.57 \ m$

(B) Time spent by the ball on air

Time of flight = Time to reach maximum height + time to hit ground.

Time to reach maximum height = time to hit ground.

Time to reach maximum height is given by;

v = u - gt

u = gt

$t = \frac{u}{g}$

Time of flight, T = 2t

$T = \frac{2u}{g}\\\\ T = \frac{2*28.2}{9.8}\\\\ T = 5.76 \ s$

(C) the position of the ball at 12 m/s

As the ball moves upwards, the speed drops, then the height of the ball when the speed drops to 12m/s will be calculated by applying the equation below.

v² = u² - 2gh

12² = 28.2² - 2(9.8)h

12² - 28.2² = - 2(9.8)h

-651.24 = -19.6h

h = 651.24 / 19.6

h = 33.23 m

Thus, at 33.23 m the speed will be 12 m/s

6 0

3 years ago

A long straight wire carries current to the right of the page. A rectangular loop is positioned directly under the wire in the p

slavikrds [6]

Answer:

Correct option A.

The net force exerted by this loop on the straight wire with the current is directed TOWARDS THE LOOP

Explanation:

The magnetic field exerts a force on a current-carrying wire in a direction given by the right-hand rule 1 (the same direction as that on the individual moving charges). This force can easily be large enough to move the wire since typical currents consist of very large numbers of moving charges.

Given that,

The wire's current is directed towards the right of the page.

The rectangular loops carry current in a clockwise direction.

Since the 'dot' field is increasing hence the induced magnetic field is 'cross', i.e. into the page and by the right-hand rule, the induced current is clockwise.

Then the magnetic field is into the page.

Since was known that

F= iL×B

Note the current is through the wire. Then, the length is in direction of the current.

Note: this equation gives the magnetic force that acts on a length L of a straight wire carrying a current (i) and immersed in a uniform magnetic field (B), that is perpendicular to the wire.

So, the magnetic field is always perpendicular to the current.

So using right hand rule,

F = i(L×B)

The length is to the right i.e. +x direction and the Magnetic field is perpendicular to the plane, i.e. in the +z direction

F = i (L•i × B•k)

F = iLB (i×k)

F = iLB•(-j)

F = -iLB•j

Then, the force is in the negative y-direction i.e. towards the loop.

8 0

4 years ago

Which of the following is true about centripetal force? Check all that apply.

Artemon [7]

<u>The following statements are true about centripetal force :</u>

Without centripetal force, an object would continue in a straight
line.
Gravity can be a centripetal force, such as when it pulls a thrown
baseball down to the ground.
Friction can be a centripetal force, such as when it keeps a car on the road going around a curve.

Answer: Option A, C, and D

<u>Explanation: </u>

Centripetal Force & Examples-

Centripetal force can be defined as the component of force that acts on an object in a curvilinear motion, directed towards the centre of axis of the circular path. This is the force responsible to pull an object in an inward direction and balance the pace on the path.

In the absence of the centripetal force, an object will either move in the direction of motion or on a straight path instead of moving inwards. It's also called as an "inward Force" as it tends to move the object towards the centre of the curved path.

As an example, a car moving on a circular road accelerates due to its constant change in direction since it's moving on a circular path. Now, the frictional force comes into picture that contributes its component as a centripetal force, pulling it towards the centre of the axis of the circular path.

Hence we can say that when a car turns on a circular path, friction force acts a centripetal force to maintain its motion and direction on the path. Talking about a baseball which is attracted by the gravitational force of the Earth and hence falls on the ground is clearly not the case of centripetal force as the path may not be circular every time and there is not axis of rotation.

Besides centripetal force, there is another force that acts on an object moving on a circular path but not in the inward direction. It is instead, equal and opposite of the centripetal force that draws the object away from the circular path of motion. Hence, it's called the "Outward force".

4 0

3 years ago

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