Given:
Teddy has two sisters. One of them is 3 years younger than Teddy, the other one is 7 years younger than her only brother.
To find:
The age of older sister at the time when the younger sister was born.
Solution:
Let the age of Teddy be x.
One sister is 3 years younger than Teddy.
Age of one sister = x-3 years
The other one is 7 years younger than her only brother. It means other sister is 7 years younger than Teddy.
Age of other sister = x-7 years
Clearly (x-3) > (x-7). So, difference between the ages of sisters is



Therefore, the age of older sister is 4 years when the younger sister was born.
Answer:
C. 22, 27
Step-by-step explanation:
Its adding +5
Step-by-step explanation:
do you want to find r?
so do 4252.50/ (18000*54)
Answer:
To simply a equation you need to use Pemdas
the order of operations.
We need to simplify parethesis first...
if you cant simplify in it like (x+3)
you need to use the distributive property
-2 *x
-2*3
6 is the greatest common factor of 12 and 30