Answer:
3x + 14 items
Step-by-step explanation:
First plant produces 5x + 11 items
Second plant produces 2x - 3 items
First plant production - second plant production = 5x + 11 - (2x - 3)
5x + 11 - 2x + 3 = 3x + 14 items
<h3>
Answer: 6 dollars per kilogram</h3>
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Explanation:
The mixed number 4 & 1/2 converts to the decimal form 4.5
The unit price is 27/(4.5) = 6 dollars per kilogram
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If you wanted, you can think of it like this ratio
4.5 kg : 27 dollars
Dividing both parts of that ratio by 4.5 will lead to
1 kg : 6 dollars
Answer:
The answer to your question is (x + 7)² + (y - 5)² = 88
Step-by-step explanation:
Equation
x² + 14x + y² - 10y = 14
Complete perfect trinomial squares
x² + 14x + (7)² + y² - 10y + (5)² = 14 + (7)² + (5)²
Simplify
x² + 14x + (7)² + y² - 10y + (5)² = 14 + 49 + 25
x² + 14x + (7)² + y² - 10y + (5)² = 88
Factor
(x + 7)² + (y - 5)² = 88 This is the equation in the form
center-radius
Function h has the largest y-intercept which is 44
Step-by-step explanation:
Any linear function is represented in the form

Here b is the y-intercept of the linear function i.e. the constant term in the function.
We will compare all the functions with the general form we get
y-intercept of f(x) = 1
y-intercept of g(x) = 8
y-intercept of h(x) = 44
y-intercept of j(x) = 0
Hence,
Function h has the largest y-intercept which is 44
Keywords: intercepts, linear functions
Learn more about intercepts at:
#LearnwithBrainly
The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.
Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>
We calculate the cross product as a determinant of (i,j,k) and the normal products
i j k
5 -1 -6
1 1 1
=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>
Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0
Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.