2 years ago

Which function below is the inverse of f(x)= 7x-1/2

1 answer:

8 0

$f(x)=7x-\dfrac{1}{2}\to y=7x-\dfrac{1}{2}\\\\\text{we change x to y and y to x}\\\\x=7y-\dfrac{1}{2}\\\\\text{solve for y}\\\\7y-\dfrac{1}{2}=x\ \ \ \ |+\dfrac{1}{2}\\\\7y=x+\dfrac{1}{2}\ \ \ \ \ |:7\\\\\boxed{y=\dfrac{1}{7}x+\dfrac{1}{14}}\\\\Answer:\ \boxed{f^{-1}(x)=\dfrac{1}{7}x+\dfrac{1}{14}}$

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after 5 years of earning at an annual rate of 4 percent, an investment has earned 1200 in interest. determine the amount of the

8_murik_8 [283]

$\bf ~~~~~~ \textit{Simple Interest Earned}
\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\to &\$1200\\
P=\textit{original amount deposited}\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
t=years\to &5
\end{cases}
\\\\\\
1200=P(0.04)(5)\implies \cfrac{1200}{(0.04)(5)}=P\implies 6000=P$

3 0

2 years ago

Simplify.

Sidana [21]

<h3>Answer: $3\sqrt{7}$ </h3>

3*sqrt(7)

3 times the square root of 7

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Explanation:

I'm assuming the V stands for square root. You can write sqrt(63).

$\sqrt{63} = \sqrt{9*7}\\\\\sqrt{63} = \sqrt{9}*\sqrt{7}\\\\\sqrt{63} = 3\sqrt{7}$

The idea is to factor 63 in such a way that one factor is the largest perfect square possible, that way we can pull the root apart to simplify as shown above. The rule I used for the second step is $\sqrt{x*y} = \sqrt{x}*\sqrt{y}$