The valid prediction for the mean of the population possible using these samples is C. Yes, the variation of the sample means is small
<h3>What is a sample mean?</h3>
It should be noted that a sample mean is an average of a set of data . Also, the sample mean can be used to calculate the standard deviation, central tendency, and the variance of a data set.
The sample mean can be applied to a variety of uses, including calculating population averages.
Here, the sample variance is a measure of the degree to which the numbers in a list are spread out. Here, the numbers given are close to each other.
If the numbers in a list are all close to the expected values, the variance will be small and if they are far away, the variance will be large.
Therefore, the correct option is C.
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I didn’t see an image or anything but I looked it up and it said regular polygons, since they have the sides all the same length they must always be in the same proportions, and their interior angles are always the same.
so 1.25 is the right answer not sure tho
<h3>hope it would be helpful </h3>
Step-by-step explanation:
y = 3 + 8x^(³/₂), 0 ≤ x ≤ 1
dy/dx = 12√x
Arc length is:
s = ∫ ds
s = ∫₀¹ √(1 + (dy/dx)²) dx
s = ∫₀¹ √(1 + (12√x)²) dx
s = ∫₀¹ √(1 + 144x) dx
If u = 1 + 144x, then du = 144 dx.
s = 1/144 ∫ √u du
s = 1/144 (⅔ u^(³/₂))
s = 1/216 u^(³/₂)
Substitute back:
s = 1/216 (1 + 144x)^(³/₂)
Evaluate between x=0 and x=1.
s = [1/216 (1 + 144)^(³/₂)] − [1/216 (1 + 0)^(³/₂)]
s = 1/216 (145)^(³/₂) − 1/216
s = (145√145 − 1) / 216
