Answer:
The probability that a performance evaluation will include at least one plant outside the United States is 0.836.
Step-by-step explanation:
Total plants = 11
Domestic plants = 7
Outside the US plants = 4
Suppose X is the number of plants outside the US which are selected for the performance evaluation. We need to compute the probability that at least 1 out of the 4 plants selected are outside the United States i.e. P(X≥1). To compute this, we will use the binomial distribution formula:
P(X=x) = ⁿCₓ pˣ qⁿ⁻ˣ
where n = total no. of trials
x = no. of successful trials
p = probability of success
q = probability of failure
Here we have n=4, p=4/11 and q=7/11
P(X≥1) = 1 - P(X<1)
= 1 - P(X=0)
= 1 - ⁴C₀ * (4/11)⁰ * (7/11)⁴⁻⁰
= 1 - 0.16399
P(X≥1) = 0.836
The probability that a performance evaluation will include at least one plant outside the United States is 0.836.
Answer:
88.46%
Step-by-step explanation:
433 - 383 = 50
50 ÷ 433 = 0.1154
0.1154 x 100 = 11.54%
100% - 11.54% = 88.46%
<u>Check work:</u>
433 x 88.46% = 383
X times 0.05 = $50
Solve for x
We do the inverse of times which is divide
$50 divide by 0.05 = $1000
Thus, $1000 is the amount of loan.
-12(-3) + 7
First, simplify 12 × (-3) to get -36. / Your problem should look like:
Second, add 36 + 7. / Your problem should look like: 43
Answer:
43
It’s 0.775x +2.5 =correct
