One lead atom, two nitrogen atoms, four oxygen atoms.
Answer:
Equilibrium constant is: 1.09
Explanation:
The proposed equilibrium is:
2NH₃(g) ⇄ 3H₂(g)+N₂(g)
Concentrations are: [NH₃] = 0.250 M; [H₂] = 0.440 M; [N₂] = 0.800 M
Expression for Kc is: [H₂]³ . [N₂] / [NH₃]²
We replace data → Kc = (0.440³ . 0.800) / 0.250²
Kc = 1.09
Remember that equilibrium constant has no units and it depends on T°
It should be D, cells are parts, tissue is part and organ is part of a system.
Answer:
After 3 half lives 10 g of radio active material left.
Explanation:
Given data:
Total amount of radio active material = 80 g
Amount left after 3 half lives = ?
Solution:
At time zero = 80 g
At first half life = 80 g/2 = 40 g
At 2nd half life = 40 g/2 = 20 g
At 3rd half life = 20 g/2 = 10 g
Thus, after 3 half lives 10 g of radio active material left.
