How many real roots and how many complex roots exist for the polynomial
1 answer:
Answer:
D. 4 real roots and 0 complex roots
Step-by-step explanation:
If I assume that the function you are saying is
There should be up to "4 roots," there can't be more or less than 4 total solutions. First, we need to check how many sign changes are there in this function. There are 3 positive real roots. Now lets check for negative roots.
There are is only 1 negative real root. Since we basically have 4 real roots, and the max is 4. There should be 4 real roots and 0 complex roots.
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Answer:
A) reflection across the y-axis
Step-by-step explanation:
If , then this says that two
-coordinates are equal for opposite values of
.
Let a point on
.
Then .
We also know that and therefore
is also a point on the graph.
If you graph [/tex](-a,b)[/tex] and you will see they are symmetrical to each about the
-axis.
Example if given both and
, then
. This means both (2,3) and (-2,3) are points on the graph.
Here is what those two points look like on a Cartesian Plane (please see graph in picture).
