X = 7
8(7) = 5(7) + 21
56 = 35 + 21
56 = 56
Answer:
(3,11)
Step-by-step explanation:
Turn both equations into linear equations:
y=2x+5
y=5x-4
Then, just graph both equations.
Find the point where the two lines intersect. That point of intersection is the solution. That coordinate is (3,11).
You would first substitute -7 for m and 2 for n. It would look like this: 4| -7-2 | . we first solve the absolute value because it is the first step in PEMDAS or order of operations. -7-2 is equal to -9. Our equation should look like this now: 4 |-9| . we solve the absolute value portion, the absolute value of a negative number is the the same number but positive. the absolute value would be 9. (we just take the negative symbol off). we now have 4 x 9. This is equal to 36.
36 is the answer.
Answer:
-10,-13,-16 and importance of being in a good night friends ni pta nhi hai to you
1.Drawn a straight line AB=7 cm with the help of ruler.
2.With the help of compass drawn an arc from A and at the point where it cuts AB from that point made another arc drawn an arc cutting the previous arc.
3.From A drawn a straight line joining the arc and extend it to M.
4.With the help of ruler measured 5 cm and mark it as AC.
5.Joined BC and we get the required triangle.
6.From C drawn an arc and make it cut on AC and BC and from the point it cuts AC and BC drawn arc cutting each other and extend a line from point C extend a line to the point point of intersection of two arc.
7.Similarly we do for A and the point where the two line intersect denoted as O.
8.Made a perpendicular from O on AB this perpendicular will be radius and taking O as centre we draw a circle this is our incircle.
9.And AN is our locus of points equidistant from two lines AB and AC.
We need to construct a circle inscribed in triangle that is incircle it can be done by making angle bisector of two sides the point where it intersect will be incentre. The centre of required circle.
The angle bisector is the locus where points are equidistant from two sides.