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SashulF [63]
3 years ago
14

Solve the following 2(x+3)=x-4

Mathematics
2 answers:
solmaris [256]3 years ago
7 0

Answer:

x=5

Step-by-step explanation:

2(x+3)=x-4

distribute:

2x+6=x-4

+2x   +2x

6=2x-4

+4       +4

10=2x

/2    /2

x = 5

(edit: actually subtract x and then subtract 6. finally divide)

x = -10

Anna35 [415]3 years ago
7 0
Is x=5.......................
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Stanley drove his car on a business trip when he left the mleage was 840miles. And. when he returned the mileage was 1,200miles.
Elan Coil [88]
I think for this item, the rate at which the gasoline was consumed is to be calculated. To determine the distance that Stanley's car had traveled, we subtract 840 miles from 1,200 miles. That will give us an answer of 360 miles. Dividing this by 12 gallons will give us an answer of 30 miles/gal. 
3 0
4 years ago
The cost of six hens and one duck at the university poultry farm is GH₵40. While four hens and three ducks cost GH₵36. What is t
Anon25 [30]

Answer:

Step-by-step explanation:

Let's call hens h and ducks d. The first algebraic equation says that 6 hens (6h) plus (+) 1 duck (1d) cost (=) 40.

The second algebraic equations says that 4 hens (4h) plus (+) 3 ducks (3d) cost (=) 36.

The system is

6h + 1d = 40

4h + 3d = 36

The best way to go about this is to solve it by substitution since we have a 1d in the first equation. We will solve that equation for d since that makes the most sense algebraically. Doing that,

1d = 40 - 6h.

Now that we know what d equals, we can sub it into the second equation where we see a d. In order,

4h + 3d = 36 becomes

4h + 3(40 - 6h) = 36 and then simplify. By substituting into the second equation we eliminated one of the variables. You can only have 1 unknown in a single equation, and now we do!

4h + 120 - 18h = 36 and

-14h = -84 so

h = 6.

That means that each hen costs $6. Since the cost of a duck is found in the bold print equation above, we will sub in a 6 for h to solve for d:

1d = 40 - 6(6) and

d = 40 - 36 so

d = 4.

That means that each duck costs $4.

3 0
4 years ago
Niles and Bob sailed at the same time for the same length of time. Niles' sailboat traveled 36 miles at a speed of 6 mph, while
kykrilka [37]

Answer:

Niles and Bob were traveling for 6 hours.

Step-by-step explanation:

The speed or rate at which an object is moving can be computed using the formula:

s=\frac{d}{t}

Here:

<em>s</em> = speed

<em>d</em> = distance traveled

<em>t</em> = time taken

It is provided that Niles and Bob sailed at the same time for the same length of time.

Speed of Niles sailboat is, <em>s</em>₁ = 6 mph.

Distance traveled by Niles' sailboat is, <em>d</em>₁ = 36 miles.

Speed of Bob's sailboat is, <em>s</em>₂ = 16 mph.

Distance traveled by Bob's sailboat is, <em>d</em>₂ = 96 miles.

It took both Niles and Bob the same time to travel the respective distance.

Compute the time it took Niles to travel 36 miles at 6 mph speed as follows:

t_{1}=\frac{d_{1}}{s_{1}}

   =\frac{36}{6}\\=6

It took Niles 6 hours to travel 36 miles at 6 mph speed.

Compute the time it took Bob to travel 96 miles at 16 mph speed as follows:

t_{2}=\frac{d_{2}}{s_{2}}

   =\frac{96}{16}\\=6

It took Bob 6 hours to travel 96 miles at 16 mph speed.

Thus, Niles and Bob were traveling for 6 hours.

7 0
4 years ago
What is the least common denominator for adding the fractions 4/15, 1/12, and 3/8
il63 [147K]
I think you want the least common multipule (exg LCM of 2,3,4 is 12)

so we find the factors and include all of them so like this

15=3 times 5
12=2 times 2 times 3
8=2 times 2 times 2

so to include all of them we include 3 2's, 1 3 and 1 5 or 2 times 2 times 2 times 3 times 5 or 8 times 15 or 4 times 30 or 120

the LCM is 120

so 4/15=32/120
1/12=10/120
3/8=45/120

add 32/120+10/120+45/120=(32+10+45)/120=87/120
5 0
3 years ago
Read 2 more answers
I really need help with this one
Novay_Z [31]

Answer:

28

Step-by-step explanation:

Since B is the midpoint of AC, that means AB = BC. That means 3x+4 = 5x-6. We can now set up an equation to solve for x:

3x+4 = 5x-6

3x+10 = 5x

10 = 2x

x = 5

Now that we know what x is, we can just plug x into the expression of AB and multiply it by 2:

(3*(5)+4)*2

=(15+4)*2

=19*2

=28

(side note: we could have plugged x into the expression of BC as well, but in this case plugging it into AB tends to be easier to solve)

Therefore, the length of AC is 28.

3 0
3 years ago
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